BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Sequences

Expert replies
by zagcollins » Sun Jul 20, 2008 7:57 am
If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =

A.2^19
B.2^20
C.2^21
D.2^20-1
E.2^21-1
Join the discussion
Source: — Problem Solving |

by pepeprepa » Sun Jul 20, 2008 2:16 pm
x1=3
x[n+1]=2[xn]-1

x1=3
x2=5
x3=9

You can build this formula which suits to the set: x[n]=(2^n)+1
x[20]=2^20 +1
x[19]=2^19 +1

2^20 + 1 - 2^19 - 1 = 2^19 x (2-1)=2^19

--> A
Join the discussion

by zagcollins » Mon Jul 21, 2008 4:04 am
just cant understand the sum...seems tricky and tough....
Join the discussion

Re: Sequences

by Ian Stewart » Mon Jul 21, 2008 5:34 am
zagcollins wrote:If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ? 1, then x20 – x19 =

A.2^19
B.2^20
C.2^21
D.2^20-1
E.2^21-1
With a sequence question, it is almost always a good idea to write out the first few terms. Here, we know x(1) = 3. The other terms are defined by the rule:

x(n+1) = 2x(n) - 1

The (n+1)th term is the term that follows the (n)th term, so you can read the above definition as follows: "to find the next term, multiply the current term by 2, then subtract 1". In that way, we can quickly find a few terms:

x(1) = 3
x(2) = 5
x(3) = 9
x(4) = 17
x(5) = 33

What we don't want to do is find the value of x(20) and of x(19)- that could take all day. There are many ways to answer the question, but normally sequence questions test your ability to recognize a pattern. The question asks about the difference between consecutive terms: it asks for x(20) - x(19). We can look at the difference between the terms we wrote down above, and see if a pattern emerges:

x(2) - x(1) = 2 = 2^1
x(3) - x(2) = 4 = 2^2
x(4) - x(3) = 8 = 2^3
x(5) - x(4) = 16 = 2^4
and from this it seems likely that...
x(20) - x(19) = 2^19

That's not a rigorous mathematical proof, but for a GMAT sequence question, it will be a reliable method almost all of the time.

There are many ways to prove this rigorously; one is by 'mathematical induction':

x(1) = 3 = 2^1 + 1

If x(n) = 2^n + 1, then
x(n+1) = 2x(n) - 1 = 2*(2^n + 1) - 1 = 2^(n+1) + 1

So for all n, x(n) = 2^(n) + 1

Thus,
x(20) - x(19) = (2^(20) + 1) - (2^(19) + 1) = 2^20 - 2^19 = 2^19
For online GMAT math tutoring, or to buy my higher-level Quant books and problem sets, contact me at ianstewartgmat at gmail.com

ianstewartgmat.com
Join the discussion

by pepeprepa » Mon Jul 21, 2008 5:35 am
x[n] is a term of the set as x[1], x[2],x[3] ....

We know these things:
x[n+1]= 2x[n] -1 for n ≥ 1
x[1]=3

Let's calculate the followinf terms of the set till we understand how the set works.
x1=3
x2=2*3-1=5
x3=2*5-1=9
x4=2*9-1=17
x5=2*17-1=33
...

You calculate the next one till you manage to find that you can find x[n] thanks to this formula x[n]=(2^n)+1
That is just "set practice", do exercices from a maths book and you will get the habit.

Hope it's ok even if i didn't exactly catch what you didn't understand.
If someone has someting clearer (Thanks Ian for your first one method)...
Join the discussion

by zagcollins » Mon Jul 21, 2008 6:56 am
thanks Ian and Pepe...great explanation...
Join the discussion