If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ≥ 1, then x20 – x19 =
A.2^19
B.2^20
C.2^21
D.2^20-1
E.2^21-1
A.2^19
B.2^20
C.2^21
D.2^20-1
E.2^21-1
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With a sequence question, it is almost always a good idea to write out the first few terms. Here, we know x(1) = 3. The other terms are defined by the rule:zagcollins wrote:If the sequence x1, x2, x3, …, xn, … is such that x1 = 3 and xn+1 = 2xn – 1 for n ? 1, then x20 – x19 =
A.2^19
B.2^20
C.2^21
D.2^20-1
E.2^21-1
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