BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Sequence Related

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 504
Joined: Tue Apr 19, 2011 1:40 pmFollowed by: 11 members
Thanked: 114 times
by knight247 » Mon Aug 22, 2011 11:38 am
The digits of a positive integer having 3 digits when taken in order are in arithmetic progression and their sum is 18. The number obtained by reversing the digits is 396 less than the original number. Find the number
(A)468
(B)594
(C)792
(D)822
(E)864

OA is E

Detailed explanations would be appreciated. Thanks
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 965
Joined: Thu Jan 28, 2010 12:52 amFollowed by: 34 members
Thanked: 156 times
GMAT Score:720

by vineeshp » Mon Aug 22, 2011 11:59 am
First digit is a, second digit is a + d and third digit is a + 2d. (Arithmetic progression)

a + a + d + a + 2d = 18 - eq 1

The actual number is
100 * a + 10 * (a + d) + a + 2d (Just like how 123 is 1 * 100 + 2 * 10 + 3)
=
Now the reversed number:
a + 2d takes the 100th place , a + d takes 10s place and a takes units place
= 100*(a + 2d) + 10 * (a + d) + a

Difference of above 2 is 396.
(100*(a + 2d) + 10 * (a + d) + a) - (100 * a + 10 * (a + d) + a + 2d) = -396
(I initially assumed reversed is greater than original by 396. was lazy to rewrite the whole equation. Hence I did it the easy way with a minus. :) )
100 * 2d - 2d = -396
198d = -396
d = -2.

3a + 3d = 18
3a + 3 * -2 = 18
3a = 24
a=8
hence numbers are 8 , 6 and 4.
Vineesh,
Just telling you what I know and think. I am not the expert. :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Mon Aug 22, 2011 1:42 pm
knight247 wrote:The digits of a positive integer having 3 digits when taken in order are in arithmetic progression and their sum is 18. The number obtained by reversing the digits is 396 less than the original number. Find the number
(A)468
(B)594
(C)792
(D)822
(E)864

OA is E

Detailed explanations would be appreciated. Thanks
We can plug in the answer choices, which represent the 3-digit integer.

The sum of the digits must be 18.
Eliminate D (since 8+2+2≠18).

When the digits are taken in order, they must be in arithmetic progression.
Thus, the 3 digits must be equally spaced.
Eliminate B (since 4-5-9 is not equally spaced).
Eliminate C (since 2-7-9 is not equally spaced).

When the digits are reversed, the result must be 396 less than the original number.
Thus, the units digit must be smaller than the hundreds digit.
Eliminate A (since the units digit 8 is larger than the hundreds digit 4).

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 106
Joined: Fri Feb 05, 2010 9:39 amFollowed by: 1 member
Thanked: 4 times

by czarczar » Tue Aug 23, 2011 9:21 am
knight247 wrote:The digits of a positive integer having 3 digits when taken in order are in arithmetic progression and their sum is 18. The number obtained by reversing the digits is 396 less than the original number. Find the number
(A)468
(B)594
(C)792
(D)822
(E)864

OA is E

I just tried with the answer choices and got E.

As 864-396 = 468 (Reverse of original number).
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Master | Next Rank: 500 Posts
Posts: 106
Joined: Fri Feb 05, 2010 9:39 amFollowed by: 1 member
Thanked: 4 times

by czarczar » Tue Aug 23, 2011 9:23 am
GMATGuruNY wrote:
knight247 wrote:The digits of a positive integer having 3 digits when taken in order are in arithmetic progression and their sum is 18. The number obtained by reversing the digits is 396 less than the original number. Find the number
(A)468
(B)594
(C)792
(D)822
(E)864

OA is E

Detailed explanations would be appreciated. Thanks
We can plug in the answer choices, which represent the 3-digit integer.

The sum of the digits must be 18.
Eliminate D (since 8+2+2≠18).

When the digits are taken in order, they must be in arithmetic progression.
Thus, the 3 digits must be equally spaced.
Eliminate B (since 4-5-9 is not equally spaced).
Eliminate C (since 2-7-9 is not equally spaced).

When the digits are reversed, the result must be 396 less than the original number.
Thus, the units digit must be smaller than the hundreds digit.
Eliminate A (since the units digit 8 is larger than the hundreds digit 4).

The correct answer is E.
Thanks sir!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1