Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Seeking an answer on another question

Expert replies
by desihokie » Sun Jan 13, 2008 11:23 pm
please explain.
You do not have the required permissions to view the files attached to this post.
Join the discussion
Source: — Problem Solving |

by simplyjat » Sun Jan 13, 2008 11:35 pm
Let "a" be the constant increment in height of the tree, then height of the tree after six years is (4+6a) and height of the tree after four years is (4+4a).
Now we know that height of the tree at six years was 1/5 greater than height at 4 years. Thus we have the following equation

(4+6a) = (6/5) (4+4a) { 6/5 is 1/5 greater than one}
solving we get a = 2/3
simplyjat
Join the discussion

by Stuart@KaplanGMAT » Sun Jan 13, 2008 11:35 pm
We can solve this algebraically or by backsolving.

First, the algebraic solution:

Let's let the amount of growth per year be x.

So, at the end of 4 years, the tree will be 4 + 4x feet tall.

At the end of 6 years, the tree is is 4 + 6x feet tall, but since we know the relationship between yr 6 and yr 4, we also know that at the end of 6 years the tree will be 6/5 (4 + 4x) feet tall.

So, 4 + 6x = 6/5(4+4x)

4 + 6x = 24/5 + 24/5(x)
(let's multiply both sides by 5 to elimiate the fractions)

20 + 30x = 24 + 24x
30x - 24x = 24 - 20
6x = 4

x = 4/6 = 2/3

Backsolving involves working backward from the answer choices. We generally want to start with either (b) or (d) (so we don't have to check as many choices).

If we start with (d), we're assuming that the tree grows 2/3 of a foot per year.

So, after 4 years the tree would be 4 + 4(2/3) = 12/3. + 8/3 = 20/3 feet tall.

After 6 years, the tree would be 4 + 6(2/3) = 12/3 + 12/3 = 24/3 = 8 feet tall.

Now we ask, is 8 = (6/5)(20/3)?

6/5(20/3) = 120/15 = 8.

So, if we pick 2/3 of a foot per year, we get the correct ending to the story (i.e. 6/5(yr4) = yr6) - therefore answer (d) is correct.
Image

Stuart Kovinsky | Kaplan GMAT Faculty | Toronto

Kaplan Exclusive: The Official Test Day Experience | Ready to Take a Free Practice Test? | Kaplan/Beat the GMAT Member Discount
BTG100 for $100 off a full course
Join the discussion

by desihokie » Sun Jan 13, 2008 11:57 pm
[quote="simplyjat"]Let "a" be the constant increment in height of the tree, then height of the tree after six years is (4+6a) and height of the tree after four years is (4+4a).
Now we know that height of the tree at six years was 1/5 greater than height at 4 years. Thus we have the following equation

(4+6a) = (6/5) (4+4a) { 6/5 is 1/5 greater than one}
solving we get a = 2/3[/quote]

Thank you very much to both of you for your reply. I was doing a silly mistake. Instead of multiplying by 6/5 i was doing this:

(4+6a) = 4+4a + 1/5, which is obviously wrong.

also, could you please answer to another question i posted here (on geometry)....just a couple of posts below? TIA
Join the discussion