We can solve this algebraically or by backsolving.
First, the algebraic solution:
Let's let the amount of growth per year be x.
So, at the end of 4 years, the tree will be 4 + 4x feet tall.
At the end of 6 years, the tree is is 4 + 6x feet tall, but since we know the relationship between yr 6 and yr 4, we also know that at the end of 6 years the tree will be 6/5 (4 + 4x) feet tall.
So, 4 + 6x = 6/5(4+4x)
4 + 6x = 24/5 + 24/5(x)
(let's multiply both sides by 5 to elimiate the fractions)
20 + 30x = 24 + 24x
30x - 24x = 24 - 20
6x = 4
x = 4/6 = 2/3
Backsolving involves working backward from the answer choices. We generally want to start with either (b) or (d) (so we don't have to check as many choices).
If we start with (d), we're assuming that the tree grows 2/3 of a foot per year.
So, after 4 years the tree would be 4 + 4(2/3) = 12/3. + 8/3 = 20/3 feet tall.
After 6 years, the tree would be 4 + 6(2/3) = 12/3 + 12/3 = 24/3 = 8 feet tall.
Now we ask, is 8 = (6/5)(20/3)?
6/5(20/3) = 120/15 = 8.
So, if we pick 2/3 of a foot per year, we get the correct ending to the story (i.e. 6/5(yr4) = yr6) - therefore answer (d) is correct.