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mixture issue

by vishugogo » Thu Jan 17, 2013 1:27 am
In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:1. Both mixtures are emptied into a 3rd container C3. What will be the ratio of water:milk in C3.

Source: Grockit

A) 3:4
B) 10:3
C) 6:5
D) 3:7
E) 1:2

OA...D

KINLDY EXPLAIN IN DETAIL...:)
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by e-GMAT » Thu Jan 17, 2013 2:01 am
vishugogo wrote:In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:1. Both mixtures are emptied into a 3rd container C3. What will be the ratio of water:milk in C3.

Source: Grockit

A) 3:4
B) 10:3
C) 6:5
D) 3:7
E) 1:2

OA...D

KINLDY EXPLAIN IN DETAIL...:)
I think there is some part missing in the question.

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

C1 Container--

Say water is 3 ltr., so milk would be 2 lit., & hence total mixture would be 5 lit.

C2 Container--

Say water is 4 ltr., so milk would be 1 lit., & hence total mixture would be 5 lit.

C3 Container--I consider that equal quantity of mixture is emptied

Total water would be 3+4=7 ltr., & milk would be 2+1=3 lit., & hence water:milk ratio would be 7:3, & not 3:7.

Hope it is clear to you.

-Shalabh Jain
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by vishugogo » Thu Jan 17, 2013 3:31 am
thank you for your reply...and yes your approach is correct on the following line

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

just a little more help on this question....if the mixture was not of equal quantity but ratios...how will I approach this question....for example of mixing ratio was 4:3...then answer will be....kindly help....:)
e-GMAT wrote:
vishugogo wrote:In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:1. Both mixtures are emptied into a 3rd container C3. What will be the ratio of water:milk in C3.

Source: Grockit

A) 3:4
B) 10:3
C) 6:5
D) 3:7
E) 1:2

OA...D

KINLDY EXPLAIN IN DETAIL...:)
I think there is some part missing in the question.

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

C1 Container--

Say water is 3 ltr., so milk would be 2 lit., & hence total mixture would be 5 lit.

C2 Container--

Say water is 4 ltr., so milk would be 1 lit., & hence total mixture would be 5 lit.

C3 Container--I consider that equal quantity of mixture is emptied

Total water would be 3+4=7 ltr., & milk would be 2+1=3 lit., & hence water:milk ratio would be 7:3, & not 3:7.

Hope it is clear to you.

-Shalabh Jain
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by e-GMAT » Thu Jan 17, 2013 9:45 pm
vishugogo wrote:thank you for your reply...and yes your approach is correct on the following line

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

just a little more help on this question....if the mixture was not of equal quantity but ratios...how will I approach this question....for example of mixing ratio was 4:3...then answer will be....kindly help....:)
e-GMAT wrote:
vishugogo wrote:In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:1. Both mixtures are emptied into a 3rd container C3. What will be the ratio of water:milk in C3.

Source: Grockit

A) 3:4
B) 10:3
C) 6:5
D) 3:7
E) 1:2

OA...D

KINLDY EXPLAIN IN DETAIL...:)
I think there is some part missing in the question.

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

C1 Container--

Say water is 3 ltr., so milk would be 2 lit., & hence total mixture would be 5 lit.

C2 Container--

Say water is 4 ltr., so milk would be 1 lit., & hence total mixture would be 5 lit.

C3 Container--I consider that equal quantity of mixture is emptied

Total water would be 3+4=7 ltr., & milk would be 2+1=3 lit., & hence water:milk ratio would be 7:3, & not 3:7.

Hope it is clear to you.

-Shalabh Jain
Let's draft another question.

In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:3. Both mixtures are emptied into a 3rd container C3 in the ratio of C1:C2::2:1. What will be the ratio of water:milk in C3.

C1 Container--

Say water is 3/(3+2)=3/5 ltr., so milk would be 2/(3+2)=2/5 lit., & hence total mixture would be 1 lit.

C2 Container--

Say water is 4/(4+3)=4/7 ltr., so milk would be 3/(4+3)=3/7 lit., & hence total mixture would be 1 lit.

Now, since C1:C2::2:1. Hence, 2 lt. of C1, & 1 lt. of C2 will be mixed.

C3 Container--

Total water would be 3/5*2+4/7=62/35 ltr., & milk would be 2/5*2+3/7=43/35 lit., & hence water:milk ratio would be 62:43.

Hope this is clear now.

-Shalabh
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by vishugogo » Thu Jan 17, 2013 10:49 pm
KUDOS!!!!.....thank you very much....:)
e-GMAT wrote:
vishugogo wrote:thank you for your reply...and yes your approach is correct on the following line

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

just a little more help on this question....if the mixture was not of equal quantity but ratios...how will I approach this question....for example of mixing ratio was 4:3...then answer will be....kindly help....:)
e-GMAT wrote:
vishugogo wrote:In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:1. Both mixtures are emptied into a 3rd container C3. What will be the ratio of water:milk in C3.

Source: Grockit

A) 3:4
B) 10:3
C) 6:5
D) 3:7
E) 1:2

OA...D

KINLDY EXPLAIN IN DETAIL...:)
I think there is some part missing in the question.

If I consider that equal quantity of mixture is emptied into C3 conatainer, then following is the approach.

C1 Container--

Say water is 3 ltr., so milk would be 2 lit., & hence total mixture would be 5 lit.

C2 Container--

Say water is 4 ltr., so milk would be 1 lit., & hence total mixture would be 5 lit.

C3 Container--I consider that equal quantity of mixture is emptied

Total water would be 3+4=7 ltr., & milk would be 2+1=3 lit., & hence water:milk ratio would be 7:3, & not 3:7.

Hope it is clear to you.

-Shalabh Jain
Let's draft another question.

In a container C1 water:milk ratio is 3:2 and in C2 water:milk ratio is 4:3. Both mixtures are emptied into a 3rd container C3 in the ratio of C1:C2::2:1. What will be the ratio of water:milk in C3.

C1 Container--

Say water is 3/(3+2)=3/5 ltr., so milk would be 2/(3+2)=2/5 lit., & hence total mixture would be 1 lit.

C2 Container--

Say water is 4/(4+3)=4/7 ltr., so milk would be 3/(4+3)=3/7 lit., & hence total mixture would be 1 lit.

Now, since C1:C2::2:1. Hence, 2 lt. of C1, & 1 lt. of C2 will be mixed.

C3 Container--

Total water would be 3/5*2+4/7=62/35 ltr., & milk would be 2/5*2+3/7=43/35 lit., & hence water:milk ratio would be 62:43.

Hope this is clear now.

-Shalabh
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