sanju09 wrote:Last year the average (arithmetic mean) salary of the 10 employees of Company X was $42,800. What is the average (arithmetic mean) salary of the same 10 employees this year?
(1) For 8 of the 10 employees, this year's salary is 15 percent greater than last year's salary.
(2) For 2 of the 10 employees, this year's salary is the same as last year's salary.
I received a PM asking me to comment.
Sum of the salaries last year = number*average = (10)(42,800) = 428,000.
Statements 1 and 2 combined:
Case 1: The 8 employees in statement 1 each earned $50,000 last year
Sum of their salaries last year = 8(50,000) = 400,000.
New sum this year = 1.15(400,000) = 460,000.
Sum of the salaries of the other 2 employees last year and this year = 428,000-400,000 = 28,000.
Average this year = (460,000+28,000)/10 = 48,800.
Case 2: The 8 employees in statement 1 each earned $1000 last year
Sum of their salaries last year = 8(1,000) = 8,000.
New sum this year = 1.15(8,000) = 9200.
Sum of the salaries of the other 2 employees last year and this year = 428,000-8,000 = 420,000.
Average this year = (9200+420,000)/10 = 42,920.
Since different averages this year are possible, INSUFFICIENT.
The correct answer is
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