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Roots

by phoenix9801 » Thu Jun 17, 2010 6:24 am
I need some clarification of the 2 problems please. If you can explain step-by-step instruction I would greatly appreciate it. Be Simple...


Problem 1

2(( square root 4 + square root 8) -2 (1 + square root)) ^2




Problem 2

(2pm^-1q^0)^-4 * 2m^-1p^3 / 2pq^2
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by kvcpk » Thu Jun 17, 2010 6:26 am
phoenix9801 wrote:I need some clarification of the 2 problems please. If you can explain step-by-step instruction I would greatly appreciate it. Be Simple...


Problem 1

2(( square root 4 + square root 8) -2 (1 + square root)) ^2
Can you plz retype problem1?
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by kvcpk » Thu Jun 17, 2010 6:31 am
Totally confused with the question.

Can you please type it this way..
for example A power B power C

Type as Power(A,Power(B,C))

This should be easy to comprehend.
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by phoenix9801 » Thu Jun 17, 2010 6:32 am
kvcpk wrote:
phoenix9801 wrote:I need some clarification of the 2 problems please. If you can explain step-by-step instruction I would greatly appreciate it. Be Simple...


Problem 1

2(( square root 4 + square root 8) -2 (1 + square root)) ^2
Can you plz retype problem1?
Sure....

2((√4 + √8) -2(1 + √8))^2
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by jube » Thu Jun 17, 2010 6:34 am
phoenix9801 wrote: Problem 2

(2pm^-1q^0)^-4 * 2m^-1p^3 / 2pq^2
Is the first term (2pm^-1)(q^0)?
And is the second term: (2m^-1)(p^3)/2pq^2 or (2m^-1)(p^3 / 2pq^2)
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by jube » Thu Jun 17, 2010 6:38 am
2((√4 + √8) -2(1 + √8))^2

= 2[(2 + 2√2) -2(1 +2√2)]^2
= 2[2 +2√2 -2 -4√2]^2
= 2[2√2(1 - 2)]^2
= 2.[-2√2]^2
=2.4.2
=16
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by kvcpk » Thu Jun 17, 2010 6:44 am
If you observe carefully, in
2((√4 + √8) -2(1 + √8))^2

√4 = 2

so internal value = 2 + √8 - 2 - 2√8
= 2 * (-√8)^2
= 2 *8 = 16
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by jube » Thu Jun 17, 2010 6:46 am
kvcpk wrote:If you observe carefully, in
2((√4 + √8) -2(1 + √8))^2

√4 = 2

so internal value = 2 + √8 - 2 - 2√8
= 2 * (-√8)^2
= 2 *8 = 16
heh. i was complicating things. good point!
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by phoenix9801 » Thu Jun 17, 2010 7:46 pm
jube wrote:2((√4 + √8) -2(1 + √8))^2

= 2[(2 + 2√2) -2(1 +2√2)]^2
= 2[2 +2√2 -2 -4√2]^2
= 2[2√2(1 - 2)]^2
= 2.[-2√2]^2
=2.4.2
=16

Hi, I wanted to be clear.....

= 2[2√2(1 - 2)]^2
>>> (how did you get 1 - 2)

= 2.[-2√2]^2
>>> (what happen to -1 from 1-2)

=2.4.2
>>>(last question where did you get 4 please)
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by amising6 » Thu Jun 17, 2010 7:55 pm
2((√4 + √8) -2(1 + √8))^2
2((2+2√2)-2(1+2√2))^2 (√4 === 2 as √4 is always positive)
2(2+2√2 -2 -4√2)^2
2(-2√2)^2
2(8) since (-2√2)^2=(-2√2*-2√2)=8
=16
Ideation without execution is delusion
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