Is quadrilateral ABCD a rhombus?
1. AC is perpendicular to BD
2. AB + CD = BC + AD
OA - E
Can someone explain?
1. AC is perpendicular to BD
2. AB + CD = BC + AD
OA - E
Can someone explain?
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...not necessarily, the diagonals can bisect to form a 90-degree angle without necessarily having a square. To prove to yourself draw 2 lines that intersect at 90-deg and make one of the lines much longer than the other, then connect all the ends to form quadrilateral... this is not necessarily a square.crackgmat007 wrote:A square is a rhombus. From 1, since diagonals bisect, can we not say that the quadrilatoral is a square?
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