Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

right triangles

Expert replies
Source: — Problem Solving |

by aneesh.kg » Mon Jun 11, 2012 10:46 am
Q1:
Area of shaded region = 1/3*(Area of lmn)
Area of lmn = (3)^0.5/4 *(side)^2
Since side = 6 units,
Area of lmn = 9*(3)^0.3
Area of shaded region = (1/3)*(9)*(3)^0.5 = 3*(3)^0.5

[spoiler](C)[/spoiler] is correct.
Aneesh Bangia
GMAT Math Coach
[email protected]

GMATPad:
Facebook Page: https://www.facebook.com/GMATPad
Join the discussion

by aneesh.kg » Mon Jun 11, 2012 10:49 am
Q2:
Ratio of the sides given
= (27/36)^0.5
= (3)^0.5 / 2

In a right angled triangle which has angles of 90, 60 and 30 (in degrees), the ratio
hypotenuse:second longest side:shortest side = 2:3^(0.5):1

Since the ratio of the given sides is (3)^0.5 /2, the angle opposite to the side measuring (27)^0.5 must be 60 degrees.

[spoiler](C)[/spoiler] is correct.
Aneesh Bangia
GMAT Math Coach
[email protected]

GMATPad:
Facebook Page: https://www.facebook.com/GMATPad
Join the discussion

by aneesh.kg » Mon Jun 11, 2012 10:52 am
Q3:
AC = 4 in
If side of the square is 'a',
AC = (2)^0.5 times a
(2)^0.5 * a = 4
a = 2(2)^0.5

Area of square = a^2 = 8 square inches

[spoiler](C)[/spoiler] is correct.
Aneesh Bangia
GMAT Math Coach
[email protected]

GMATPad:
Facebook Page: https://www.facebook.com/GMATPad
Join the discussion

by Mike@Magoosh » Mon Jun 11, 2012 10:53 am
Dear phoenix9801

Hi, there. I'm happy to help with these. Incidentally, I like the 9801 = 99^2 in your screenname.

For the first, it is awfully helpful to know that the area of an equilateral triangle of side s is
A = sqrt(3)*(s^2)/4
See this blog for an explanation:
https://magoosh.com/gmat/2012/gmat-math- ... emorizing/

Given that, area of the the whole equilateral is sqrt(3)*(6^2)/4 = 9sqrt(3), so one third of that is 3sqrt(3), answer C.

For the second, we know the hypotenuse is sqrt(36) = 6, and we know the long leg is sqrt(27) = 3*sqrt(3). With the Pythagorean Theorem, we can figure out, the square of the short leg is 9, so the length of the short leg is 3. This is a right triangle in which the short leg is half the length of the hypotenuse --- that has to be a 30-60-90 triangle. See this blog
https://magoosh.com/gmat/2012/the-gmats- ... triangles/
So the angle opposite the long leg in a 30-60-90 triangle is 60 degrees, answer = C.

For the third, we need the other special triangle, also discussed at
https://magoosh.com/gmat/2012/the-gmats- ... triangles/
We need the 45-45-90 triangle. Here's a quick approach. Let the side of the square = x. Then, consider right triangle ADC --- by the Pythagorean Theorem,
x^2 + x^2 = 4^2
2*x^2 = 16
x^2 = 8

Well, we need do nothing else. The side of the square, squared, is 8, which means the area = 8. Answer choice = C.

Does all that make sense?

Mike :-)
Magoosh GMAT Instructor
https://gmat.magoosh.com/
Join the discussion