Hi there,
I just had a quick question if anyone can help explain this to me!
The preceding diagram shows a figure composed of a right triangle ABC adjacent to semicircle Arc AC. If AB = OB = x, what is the perimeter of the figure?
Initially, since it is a right triangle, I would have assumed that length BC (hypotenuse of right triangle in the given figure) was x root 3, because the other sides of the right triangle are x and 2x (typically what I would associate as a 30-60-90 triangle). But in the solution, they use pythagorean theorem to solve for the length of BC instead. Why would assuming this be wrong in this case?
Thanks so much for the help!
$$\sqrt{ }$$
I just had a quick question if anyone can help explain this to me!
The preceding diagram shows a figure composed of a right triangle ABC adjacent to semicircle Arc AC. If AB = OB = x, what is the perimeter of the figure?
Initially, since it is a right triangle, I would have assumed that length BC (hypotenuse of right triangle in the given figure) was x root 3, because the other sides of the right triangle are x and 2x (typically what I would associate as a 30-60-90 triangle). But in the solution, they use pythagorean theorem to solve for the length of BC instead. Why would assuming this be wrong in this case?
Thanks so much for the help!
$$\sqrt{ }$$
