if n and m are positive integers , what is the reminder when 3 ^ (4n + 2) + M is divided by 10
n= 2
m=1
n= 2
m=1
Will Win
IMO C
I assume that this is the expression - [3 ^ (4n + 2)] + M.
(1) and (2) are clearly insufficient alone. Because, the value of m or n can be any no and when divided by 10, you get different possible remainders.
Take n=2, 3 ^ (8+2) + M = 3^10 + M = 59049 + M. M could take any value from 0-9 and when added with the 59049 and divided by 10, different remainder values turn up.
Combined, only then it is sufficient.
