If p and n are positive integers p >n , what is the remainder when p^2-n^2 is divided by 15
The remainder when p+q is divided by 5 is 1
The remainder when p-q is divided by 3 is 1
Remainder
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- cubicle_bound_misfit
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imo E...
For statement1,The remainder when p+q is divided by 5 is 1p=5 q=1---remainder is 9
p=4 q=2---remainder is 12
p=7 q=4----remainder is 3--------Insufficient
For stmt 2,
The remainder when p-q is divided by 3 is 1
p=5 q=1 -----remainder is 12
p=7 q=1-----remainder is 3--insufficient
By combining both,again we have two different remainders.So insufficient..
....
For statement1,The remainder when p+q is divided by 5 is 1p=5 q=1---remainder is 9
p=4 q=2---remainder is 12
p=7 q=4----remainder is 3--------Insufficient
For stmt 2,
The remainder when p-q is divided by 3 is 1
p=5 q=1 -----remainder is 12
p=7 q=1-----remainder is 3--insufficient
By combining both,again we have two different remainders.So insufficient..
....
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statement 1:
It states that when p+q is divided by 5 the remainder is 1
so lets assume the no to be 5n+1 ( here n=0,1,2,3...etc)
p+q=5n+1
Insufficient
statement 2:
It states that when p-q is divided by 3 the remainder is 1
so lets assume the no to be 3n+1 ( here n=0,1,2,3...etc)
p-q = 3n+1
Insufficient
Now,lets combine both the statements and see whether we can deduce a solution
for n=1
p+q=6
p-q=4
2p=10
p=5 and q=1
(p^2-n^2)/15=24/15..........remainder=9
for n=2
p+q=11
p-q=7
2p=18
p=9 and q=2
(p^2-n^2)/15=77/15.........remainder=2
IT is observed that the remainder varies in both the cases..
Hence E is the ans...
It states that when p+q is divided by 5 the remainder is 1
so lets assume the no to be 5n+1 ( here n=0,1,2,3...etc)
p+q=5n+1
Insufficient
statement 2:
It states that when p-q is divided by 3 the remainder is 1
so lets assume the no to be 3n+1 ( here n=0,1,2,3...etc)
p-q = 3n+1
Insufficient
Now,lets combine both the statements and see whether we can deduce a solution
for n=1
p+q=6
p-q=4
2p=10
p=5 and q=1
(p^2-n^2)/15=24/15..........remainder=9
for n=2
p+q=11
p-q=7
2p=18
p=9 and q=2
(p^2-n^2)/15=77/15.........remainder=2
IT is observed that the remainder varies in both the cases..
Hence E is the ans...
- cubicle_bound_misfit
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well, picking no may not be the best option as in real GMAT you may have to find the .004% of 1/0.125th growth of fat level in Jay Leno's potbelly.
So better to use
p-q = 5x +1
p+q = 3Y+1 etc.
hope that helps.
So better to use
p-q = 5x +1
p+q = 3Y+1 etc.
hope that helps.
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gmat009 wrote:If p and n are positive integers p >n , what is the remainder when p^2-n^2 is divided by 15
The remainder when p+q is divided by 5 is 1
The remainder when p-q is divided by 3 is 1
Quick question, wouldn't this be obviously E since both of the statements are not mentioning n at all?
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It hink it is a typogmat2010 wrote:gmat009 wrote:If p and n are positive integers p >n , what is the remainder when p^2-n^2 is divided by 15
The remainder when p+q is divided by 5 is 1
The remainder when p-q is divided by 3 is 1
Quick question, wouldn't this be obviously E since both of the statements are not mentioning n at all?
IMHO it should be
If p and n are positive integers p >n , what is the remainder when p^2-n^2 is divided by 15
The remainder when p+n is divided by 5 is 1
The remainder when p-n is divided by 3 is 1
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anb,
Refer here https://www.beatthegmat.com/remainders-t22704.html#95683
The same problem has been discussed and I have picked numbers.
Refer here https://www.beatthegmat.com/remainders-t22704.html#95683
The same problem has been discussed and I have picked numbers.