Remainder Rules?

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Remainder Rules?

by Ryan Ziemba » Wed Jul 07, 2010 7:03 am
Are there any standard rules one should keep in mind when solving quant problems involving remainders? I had some difficulty with Problem 106 in the Problem Solving section of the Official Guide and was wondering if there is a quick and easy approach to remember when tackling these types of questions. For instance, should I start by picking numbers or backsolving?

106. When positive integer x is divided by positive integer y, the remainder is 9. If x/y=96.12, what is the value of y?

(a) 96
(b) 75
(c) 48
(d) 25
(e) 12
Source: — Problem Solving |

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by Rahul@gurome » Wed Jul 07, 2010 7:19 am
In this case, we can start by back solving. x/y=96.12 = 96 12/100
Let remainder = r
r/y = 12/100, here r = 9, then 9/y = 12/100 implies y = 9/0.12 = 75
The correct answer is (B).
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by selango » Wed Jul 07, 2010 7:32 am
The formula is,

x=d*q+r

X is the number divided.

d is dividend

q is quotient and r is remainder

-->x=y*q+9

Divide by y thru the equation.

x/y=q+9/y

We know x/y=96.12

96.12=q+9/y

96+12/100=q+9/y

By comparing both sides we get

12/100=9/y

y=75

Using the general formula,you can solve most of the remainder problems.

Hope this clarify
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by GMATGuruNY » Wed Jul 07, 2010 9:54 am
Ryan Ziemba wrote:Are there any standard rules one should keep in mind when solving quant problems involving remainders? I had some difficulty with Problem 106 in the Problem Solving section of the Official Guide and was wondering if there is a quick and easy approach to remember when tackling these types of questions. For instance, should I start by picking numbers or backsolving?

106. When positive integer x is divided by positive integer y, the remainder is 9. If x/y=96.12, what is the value of y?

(a) 96
(b) 75
(c) 48
(d) 25
(e) 12
When one number doesn't divide evenly into another number, we can represent what's left over as a decimal (5/2 = 2.5) or as a remainder (5/2 = 2 R 1). The problem above is testing the relationship between the decimal representation and the remainder representation. Here's the relationship:

decimal * divisor = remainder

Let's revisit 5/2 = 2.5. If we multiply the decimal (.5) by the divisor (2), we get .5 * 2 = 1, which is the remainder if we represent the division as 5/2 = 2 R1.

In the problem above the decimal is .12, the divisor is y, and the remainder is 9. So .12y = 9, y = 9/.12 = 900/12 = 75.

The correct answer is B.
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by Testluv » Wed Jul 07, 2010 6:11 pm
Rahul@gurome wrote:In this case, we can start by back solving. x/y=96.12 = 96 12/100
Let remainder = r
r/y = 12/100, here r = 9, then 9/y = 12/100 implies y = 9/0.12 = 75
The correct answer is (B).
awesome approach!
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