BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Remainder of 5

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 125
Joined: Mon Dec 15, 2008 9:24 pm
by joyseychow » Wed Jan 20, 2010 7:54 pm
If x and y are positive integers and x/y has a remainder of 5, what is the smallest possible value of xy?


[spoiler]This ques is from Man prep book. I don't understand why smallest value of x is 5 and not 11.[/spoiler]
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
GMAT Instructor
Posts: 1302
Joined: Mon Oct 19, 2009 2:13 pmFollowed by: 164 members
Location: Toronto
Thanked: 539 times
GMAT Score:800

by Testluv » Wed Jan 20, 2010 9:00 pm
So, you've figured out that the minimum possible value of y is 6.

But you are forgetting to consider the cases where the numerator is smaller than the denominator. Certainly, 11 is divided by 6 once, leaving a remainder of 5, or 1R5. But 5 is divided by 6 zero times, also leaving a remainder of 5, or 0R5. So, the minimum possible value of x is 5, and the minimum possible value of xy is 30.
Kaplan Teacher in Toronto
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 125
Joined: Mon Dec 15, 2008 9:24 pm

by joyseychow » Thu Jan 21, 2010 12:12 am
Testluv wrote:So, you've figured out that the minimum possible value of y is 6.

But you are forgetting to consider the cases where the numerator is smaller than the denominator. Certainly, 11 is divided by 6 once, leaving a remainder of 5, or 1R5. But 5 is divided by 6 zero times, also leaving a remainder of 5, or 0R5. So, the minimum possible value of x is 5, and the minimum possible value of xy is 30.
Ahhh!! Now I see it. Thanks!! :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1