Relaton between cube's surface area and volume

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by theCodeToGMAT » Fri Jan 10, 2014 1:39 am
Volume of Cube = V
=> Side^3 = V
=> Side = cuberoot(V)

Second Cube:
=> 6*side'^2 = 2 * 6*side^2
=> side'^2 = 2*(v)^2/3
=> side = sqrt(2) * (V)^/3

Volume = (side')^3 = 2*sqrt(2) * V

{B}
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by GMATGuruNY » Fri Jan 10, 2014 6:50 am
Surface area of a cube = 6e².
Volume of a cube = e³.

Original cube:
Let e = 1.
Then Volume = 1³ = 1.
Surface area = 6(1²) = 6.

New cube:
Surface area doubled = 2*6 = 12.
Since 6e² = 12, we get:
e² = 2
e = √2.
Volume = e³ = (√2)³ = (√2)(√2)(√2) = 2√2. This is our target.

Now plug V=1 into the answers to see which yield our target of 2√2.
Only B works:
2√2V = 2√2 * 1 = 2√2.

The correct answer is B.
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