20 * (No of members) + 25 * (No of non men) = 5500

(1) 20M = 25N + 500 (2 eqns/2 unknows - Suff)

(2) M + N = 250 (Again 2 eqns/ 2 unknows - Suff)

D IMO

Completely agree with shankar..IMO D.

shankar.ashwin wrote:20 * (No of members) + 25 * (No of non men) = 5500

(1) 20M = 25N + 500 (2 eqns/2 unknows - Suff)

(2) M + N = 250 (Again 2 eqns/ 2 unknows - Suff)

D IMO

GmatKiss wrote:At a business association conference, the registration fee for members of the association was $20 and the registration fee for nonmembers was $25. If the total receipts from registration were $5,500, did more members than nonmembers pay the registration fee?

(1) Registration receipts from members were $500 greater than receipts from nonmembers.
(2) A total of 250 people paid the registration fee.

OA : After sometime

Let total number of members = x
& total number of non-members = y

20x+25y = 5500 [GIVEN in the stem] ---- equn (1)

Stmt 1:

20X - 25y = 500 ------- equn (2)

from equation 1 and 2 we will be able to find the values of X and Y resp. [ X = 150 and y = 100]

Similarly,
from stmt 2 we have x+y = 250 ----- equn (3)

from equation 1 and 3 we will be able to find the values of x and y resp. [ X = 150 and y = 100]

Correct choice - OPTION D