A
I have nothing to add to the statement 2 explanation.
1: b is 60% greater than a. (b = 1.6a)
If a is 1, then b is 1.6 - not an integer.
a = 2 b not an integer
a=3 b not an integer
a=4 b not an integer
a=5 b is an integer = (5*1.6) = 8 5*8 = 40 no remainder when divided by 40.
a=6,7,8,9 b is not an integer.
a=10, b = 16 with 5 and 8 as factors (see a=5), so the remainder is 0 when divided by 40.
When a is a multiple of 5, b is an integer, and ab is divisible by 40 (no remainder).
1 is sufficient.
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