If a and b are positive integers, what is the remainder when ab is divided by 40?
(1) b is 60% greater than a.
(2) Each of a^2b and ab^2 is divisible by 40
positive integers
This topic has expert replies
-
- Senior | Next Rank: 100 Posts
- Posts: 69
- Joined: Wed Aug 08, 2012 9:00 am
- Followed by:1 members
- Atekihcan
- Master | Next Rank: 500 Posts
- Posts: 149
- Joined: Wed May 01, 2013 10:37 pm
- Thanked: 54 times
- Followed by:9 members
Statement 1: b = a + 60% of a = 160a/100 = 8a/5
As b is a positive integer, a must be divisible by 5.
Say, a = 5k, where k is some positive integer.
Now, ab = a*(8a/5) = (5k)*(8k) = multiple of 40
So, the remainder when ab divided by 40 is 0.
So, statement 1 is sufficient
Statement 2:
If a = 2 and b = 10, a²b = 40 and ab² = 200 are both divisible by 40 but ab = 20 leaves a remainder of 20 when divided by 40
If a = 4 and b = 10, a²b = 160 and ab² = 400 are both divisible by 40 and ab = 40 leaves a remainder of 0 when divided by 40
So, statement 2 is not sufficient
Answer : A
As b is a positive integer, a must be divisible by 5.
Say, a = 5k, where k is some positive integer.
Now, ab = a*(8a/5) = (5k)*(8k) = multiple of 40
So, the remainder when ab divided by 40 is 0.
So, statement 1 is sufficient
Statement 2:
If a = 2 and b = 10, a²b = 40 and ab² = 200 are both divisible by 40 but ab = 20 leaves a remainder of 20 when divided by 40
If a = 4 and b = 10, a²b = 160 and ab² = 400 are both divisible by 40 and ab = 40 leaves a remainder of 0 when divided by 40
So, statement 2 is not sufficient
Answer : A
- fcabanski
- Master | Next Rank: 500 Posts
- Posts: 104
- Joined: Fri Oct 07, 2011 10:23 pm
- Thanked: 36 times
- Followed by:4 members
A
I have nothing to add to the statement 2 explanation.
1: b is 60% greater than a. (b = 1.6a)
If a is 1, then b is 1.6 - not an integer.
a = 2 b not an integer
a=3 b not an integer
a=4 b not an integer
a=5 b is an integer = (5*1.6) = 8 5*8 = 40 no remainder when divided by 40.
a=6,7,8,9 b is not an integer.
a=10, b = 16 with 5 and 8 as factors (see a=5), so the remainder is 0 when divided by 40.
When a is a multiple of 5, b is an integer, and ab is divisible by 40 (no remainder).
1 is sufficient.
I have nothing to add to the statement 2 explanation.
1: b is 60% greater than a. (b = 1.6a)
If a is 1, then b is 1.6 - not an integer.
a = 2 b not an integer
a=3 b not an integer
a=4 b not an integer
a=5 b is an integer = (5*1.6) = 8 5*8 = 40 no remainder when divided by 40.
a=6,7,8,9 b is not an integer.
a=10, b = 16 with 5 and 8 as factors (see a=5), so the remainder is 0 when divided by 40.
When a is a multiple of 5, b is an integer, and ab is divisible by 40 (no remainder).
1 is sufficient.
Expert GMAT tutor.
[email protected]
If you find one of my answers helpful, please click thank.
Contact me to discuss online GMAT tutoring.
[email protected]
If you find one of my answers helpful, please click thank.
Contact me to discuss online GMAT tutoring.