BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

RE: GMAT Practice Questions

Expert replies
by CrmnKnwls » Mon Aug 09, 2010 10:52 am
I would like to know are there articles regarding these two questions?

In the rectangular coordinate plane system, the area of the triangle PQR is what fraction of the area of the triangle LMN?The following coordinates are given P(6,0) Q(8,4), R(10,0) L(2,0) M(8,12), and N(14,2)
a) 1/9 b) 1/8 c) 1/6 d) 1/5 e) 1/3

An arc is give with 100ft as the legs of the arc. The question states that the figure is a quarter of a circle. Then it goes on to say: If the land is enclosed by a fence, which of the following is closest to the length, in feet, of the fence?
a) 278 b) 341 c) 357 d) 400 e) 441
Join the discussion
Source: — Problem Solving |

by Maciek » Fri Aug 27, 2010 6:03 am
Hi CrmnKnwls!

IMO B

Formula for the area of the triangle is

A = 0.5 * base * height = 0.5 * b * h

or

A = |( Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By))/2|

Ax and Ay are the x and y coordinates of the point A, Bx and By are the x and y coordinates of the point B, and
Cx and Cy are the x and y coordinates of the point C.

A(PQR)/A(LMN) = ?
The following coordinates are given P(6,0) Q(8,4), R(10,0) L(2,0) M(8,12), and N(14,2)
Triangle PQR:

b = |PR| = 4

h = 4

A(PQR) = 0.5 * 4 * 4 = 8

Triangle LMN:

it is more difficult to calculate height so let us use the second formula

A(LMN) = |( Lx(My - Ny) + Mx(Ny - Ly) + Nx(Ly - My))/2|

A(LMN) = |( 2(12 - 2) + 8(2 - 0) + 14(0 - 12))/2)| = |( 20 + 16 - 14*12)/2| = |(36 - 168)/2| = 66

A(PQR)/A(LMN) = 8/66 = 4/33

the closest answer is b

hope it helps!

Best,
Maciek
An arc is give with 100ft as the legs of the arc. The question states that the figure is a quarter of a circle. Then it goes on to say: If the land is enclosed by a fence, which of the following is closest to the length, in feet, of the fence?
a) 278 b) 341 c) 357 d) 400 e) 441
"There is no greater wealth in a nation than that of being made up of learned citizens." Pope John Paul II

if you have any questions, send me a private message!

should you find this post useful, please click on "thanks" button :)
Join the discussion

by BastiG » Fri Aug 27, 2010 11:35 am
Can you pls post the source of these questions? I don't think that at least the first question won't be in the GMAT because it takes far too long!
Join the discussion

by diebeatsthegmat » Sun Aug 29, 2010 11:48 am
Maciek wrote:Hi CrmnKnwls!

IMO B

Formula for the area of the triangle is

A = 0.5 * base * height = 0.5 * b * h

or

A = |( Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By))/2|

Ax and Ay are the x and y coordinates of the point A, Bx and By are the x and y coordinates of the point B, and
Cx and Cy are the x and y coordinates of the point C.

A(PQR)/A(LMN) = ?
The following coordinates are given P(6,0) Q(8,4), R(10,0) L(2,0) M(8,12), and N(14,2)
Triangle PQR:

b = |PR| = 4

h = 4

A(PQR) = 0.5 * 4 * 4 = 8

Triangle LMN:

it is more difficult to calculate height so let us use the second formula

A(LMN) = |( Lx(My - Ny) + Mx(Ny - Ly) + Nx(Ly - My))/2|

A(LMN) = |( 2(12 - 2) + 8(2 - 0) + 14(0 - 12))/2)| = |( 20 + 16 - 14*12)/2| = |(36 - 168)/2| = 66

A(PQR)/A(LMN) = 8/66 = 4/33

the closest answer is b

hope it helps!

Best,
Maciek


how come h= 4 here?
An arc is give with 100ft as the legs of the arc. The question states that the figure is a quarter of a circle. Then it goes on to say: If the land is enclosed by a fence, which of the following is closest to the length, in feet, of the fence?
a) 278 b) 341 c) 357 d) 400 e) 441


how come h= 4 here?
Join the discussion

by Maciek » Sun Aug 29, 2010 12:37 pm
hi!

h = 4 because points P and R are on X-axis so you can simplify calculation:
h = Qy - 0 = 4

You can still use second formula to calculate the area of triangle PQR
A = |( Ax(By - Cy) + Bx(Cy - Ay) + Cx(Ay - By))/2|
A = |( Px(Qy - Ry) + Qx(Ry - Py) + Rx(Py - Qy))/2|
A = |( 6(4 - 0) + 8(0 - 0) + 10(0 - 4))/2| =
= |( 24 + 0 + -40)/2| = |( -16)/2| = 8

hope it helps!
Best,
Maciek
"There is no greater wealth in a nation than that of being made up of learned citizens." Pope John Paul II

if you have any questions, send me a private message!

should you find this post useful, please click on "thanks" button :)
Join the discussion