2^[(x/y)x]<1, implies (x/y)x < 0, (x^2)/y<0 ? So the question can be rephrased to
Is(x^2)/y<0
Let x = -2, y = 2, then (x^2)/y > 0.1). x < 0
Let x = -2, y = -2, then (x^2)/y < 0.
Let x = -2, y = 0, then (x^2)/y is undefined. Hence insufficient to answer the question
Let x = -2, y = -2, then (x^2)/y < 02). y < 0
Let x = +2, y = -2, then (x^2)/y < 0.
Let x = 0, y = -2, then (x^2)/y = 0. Hence insufficient to answer the question
From 1 and 2, x<0 and y<0, Sufficient to answer the question.(e.g.Let x = -2, y = -2, then (x^2)/y < 0))
IMO C
