BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Rate PS

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Legendary Member
Posts: 1665
Joined: Thu Nov 03, 2011 7:04 pm
Thanked: 165 times
Followed by:70 members

Rate PS

by karthikpandian19 » Mon Dec 26, 2011 3:28 am
Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


3
3.5
4
4.5
6
Top
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 588
Joined: Sun Oct 16, 2011 9:42 am
Location: New Delhi, India
Thanked: 130 times
Followed by:9 members
GMAT Score:720

by rijul007 » Mon Dec 26, 2011 4:29 am
karthikpandian19 wrote:Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


3
3.5
4
4.5
6
Hours walked on first day = 8hrs
Hours walked on second day = 6 hrs

speed on the first day = x km/hr
speed on the second day = (x+ 1/2) km/hr

Total distance = 8x + 6(2x+1)/2
52 = 8x + 6x + 3 = 14x + 3
x = 49/14 = 7/2 = 3.5 km/hr

Avg speed on the second day = x+0.5 = 4km/hr

Opton C
Top
User avatar
Legendary Member
Posts: 1665
Joined: Thu Nov 03, 2011 7:04 pm
Thanked: 165 times
Followed by:70 members

by karthikpandian19 » Mon Dec 26, 2011 5:31 am
Your approach made this problem look so simple....thanks
rijul007 wrote:
karthikpandian19 wrote:Tammy climbed a mountain in two days. She spent a total of 14 hours climbing the mountain. On the second day she walked at an average speed that was half a kilometer per hour faster, but 2 hours less than what she walked on the first day. If the total distance she climbed during the two days is 52 kilometers, how many kilometers per hour did Tammy walk on the second day?


3
3.5
4
4.5
6
Hours walked on first day = 8hrs
Hours walked on second day = 6 hrs

speed on the first day = x km/hr
speed on the second day = (x+ 1/2) km/hr

Total distance = 8x + 6(2x+1)/2
52 = 8x + 6x + 3 = 14x + 3
x = 49/14 = 7/2 = 3.5 km/hr

Avg speed on the second day = x+0.5 = 4km/hr

Opton C
Top
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 am
Location: Ahmedabad
Thanked: 31 times
Followed by:10 members

by ronnie1985 » Mon Dec 26, 2011 9:16 pm
x km in first day.
x/14+0.5 km/h is speed on second day.
x+12*(x/14+0.5) = 52
x = 46*7/13 = 3.5
Ans = 4
Follow your passion, Success as perceived by others shall follow you
Top
User avatar
Legendary Member
Posts: 1665
Joined: Thu Nov 03, 2011 7:04 pm
Thanked: 165 times
Followed by:70 members

by karthikpandian19 » Mon Dec 26, 2011 11:42 pm
How is 12 multiplied in the 3rd line of ur explanation
ronnie1985 wrote:x km in first day.
x/14+0.5 km/h is speed on second day.
x+12*(x/14+0.5) = 52
x = 46*7/13 = 3.5
Ans = 4
Top
User avatar
Legendary Member
Posts: 1665
Joined: Thu Nov 03, 2011 7:04 pm
Thanked: 165 times
Followed by:70 members

by karthikpandian19 » Tue Dec 27, 2011 9:33 pm
OA is C (4)
Top
Post new topic Post Reply
• Page 1 of 1