Harry’s home and his office

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Harry’s home and his office

by GmatKiss » Sun May 06, 2012 11:23 am
What is the distance between Harry's home and his office?

(1) Harry's average speed on his commute to work this Monday was 30 miles per hour.

(2) If Harry's average speed on his commute to work this Monday had been twice as fast, his trip would have been 15 minutes shorter.
Source: — Data Sufficiency |

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by aneesh.kg » Sun May 06, 2012 12:05 pm
distance = speed*time

to be able to calculate the distance, we need both his speed as well as the time of travel.

Statement (1):
Speed is known, but the time of travel not known.
INSUFFICIENT.

Statement (2):
If his average speed was 2x instead of x, we wouldve taken (t - 15) minutes instead of t minutes.
distance in both cases are equal.
d1 = d2
x*t = 2x*(t - 15)
t = 2t - 30
t = 30
We know the Time of travel, but not the speed.
INSUFFICIENT.

Upon combining both statements, we get both the speed as well as the time of travel.
Hence, the distance can be found.

[spoiler](C)[/spoiler] is the answer.
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by neelgandham » Sun May 06, 2012 12:08 pm
Let d be the distance between home and ofice.
Let s be the average speed of harry on monday.
Let t be the time taken by harry to reach office(on monday).

Then d = s x t (distance = speed * time) - equation (1)
(1) Harry's average speed on his commute to work this Monday was 30 miles per hour.
d = 30 x t - from equation (1). Since we don't know the value of t, statement I is insufficient to answer the question.
(2) If Harry's average speed on his commute to work this Monday had been twice as fast, his trip would have been 15 minutes shorter.
Travelling at his original speed, Harry would take d/s hours to reach work.
Travelling at double his original speed, Harry would take d/(2s) hours to reach work.
so, according to statement II,

(d/s) - (d/(2s)) = 1/4 (15 minutes = 1/4 hour)
d/(2s) = 1/4
d = s/2
Since we don't know the value of s, statement II is insufficient to answer the question.
Statement I and Statement II combined
d = s/2 and s = 30 miles per hour. So, the value of d = distance between Harry's home and his office [spoiler]= 15 miles[/spoiler] (Sufficient to answer the question)

IMO answer - C
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GmatKiss wrote:
Sun May 06, 2012 11:23 am
What is the distance between Harry's home and his office?

(1) Harry's average speed on his commute to work this Monday was 30 miles per hour.

(2) If Harry's average speed on his commute to work this Monday had been twice as fast, his trip would have been 15 minutes shorter.
Let d = distance between Harry's home and his office

Target question: What is the distance between Harry's home and his office?

Statement 1: Harry's average speed on his commute to work this Monday was 30 miles per hour.
To determine the distance (d), we need the travel time.
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: If Harry's average speed on his commute to work this Monday had been twice as fast, his trip would have been 15 minutes shorter.
Travel time = (distance)/(speed)
Let v = Monday's speed,

Start with a word equation:
(Monday's travel time) = (travel time at twice Monday's speed) + 15 minutes
Or..., (Monday's travel time) = (travel time at twice Monday's speed) + 0.25 hours
So, we can write d/v = d/2v + 0.25
Multiply both sides by 2v to get: 2d = d + 0.5v
Simplify: d = 0.5v
Divide both sides by v to get: d/v = 0.5
NOTE: distance/speed = time [in other words, time = d/v]
So, the Monday's travel time = 0.5 hours
So, statement 2 allows us to determine Monday's travel time, but we don't know Harry's speed.
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that Harry's speed was 30 mph
Statement 2 tells us that Harry drove for 0.5 hours
Distance = (speed)(time)
So, distance = (30)(0.5) = 15 miles
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer = C

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