BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

RATE/DISTANCE QUESTION

Expert replies
by Mclaughlin » Mon Jul 21, 2008 8:53 pm
It takes the high-speed train x hours to travel the z miles from Town A to Town B at a constant rate, while it takes the regular train y hours to travel the same distance at a constant rate. If the high-speed train leaves Town A for Town B at the same time that the regular train leaves Town B for Town A, how many more miles will the high-speed train have traveled than the regular train when the two trains pass each other?


a. z(y – x)/x + y


b. z(x – y)/x + y


c. z(x + y)/y – x


d. xy(x – y)/x + y


e. xy(y – x)/x + y
Join the discussion
Source: — Problem Solving |

by egybs » Tue Jul 22, 2008 12:07 am
I'm exhausted and about to go to bed.. but here's the solution... There is very likely a quicker way to do this, but here's an idea... I'm too tired to throw in full explanations for what's going on.. so if you can't figure out what i've done, lemme know and i'll revisit it.


Let's call time when they meet t.. so:
t = z/(z/x +z/y)
t = 1/(1/x +1/y)
t= (xy)/(x+y)

We're looking for:
tz/x - tz/y
tz (1/x - 1/y)
tz (y-x)/(xy)

put it all together:
z(xy)(y-x)/((x+y)(xy))
z(y-x)/(x+y)
which is A.
Join the discussion

by pepeprepa » Tue Jul 22, 2008 12:59 am
I think, first I try something theoric but after I would choose examples.

z=120
Train X is 40m/h so x=3h
Train is 30m/h so y=4h
The result we look for is (40/70)*120-(30/70)*120=17 and things

So now we can delete all answers with (x-y) (3-4<0) because our answer cannot be negative --> B and D out

Now let's try A)
z(y – x)/x + y
(120(4-3))(3+4)=120/7=17,14......
So it seems good

Now you can try C) E) to confirm you are right.
If you do not make fool errors it can take less than 2' but it is true it is not a fast method...
Join the discussion