faraz_jeddah wrote:
but the question asks us what is the least possible range? Should it not be 2500 as you proved it.
4500 > 2500
I feel lost.
Here's one way of thinking about it.
Let's say the highest paid member of the senior staff is A, and that the lowest paid member of the senior staff is B. We know that A = B + $4,500.
Let's also the highest paid member of the junior staff is C, and that the lowest paid member of the junior staff is D. We know that C = D + $2,000.
Now we have a few possibilities to consider.
If B makes more money than C, our salaries go A > B > C > D. Since A = B + $4,500 and B > C = D + $2,000, A is at least $6,500 greater than D, so our range is huge.
Now let's say B makes less than C but more than D. Then our salaries go A > C > B > D. Since A is still equal to B + $4,500, and D is less than B, the range is $4,500 PLUS the difference between B and D. We don't know what the range of this set is, but whatever it is, it's greater than $4,500.
Now let's say that both C and D make more money than B, but less money than A. Then our salaries go A > C > D > B, and our range is exactly $4,500.
Now let's say that we live my private heaven, where the junior staff actually make more than the executives
If C makes more than A, then our salaries go either C > A > D > B or C > A > B > D. In either case, the range is greater than $4,500, since we have the difference between A and B ($4,500) plus the difference between C and A (in both cases) and between D and B (in the first case). So again our range exceeds $4,500.
The last case is the truly remarkable one where C > D > A > B ... and again the range exceeds $4,500.
An easy way of summing all this up is that the range is difference between the greatest and least terms in a set, so that range will never shrink if you add more terms to that set, since that difference still exists. Since the range between A and B is $4,500, adding more junior members will either increase the range (as we saw in four of the five cases above) or keep it the same (if A > C > D > B).