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Ratio

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by kmittal82 » Tue Oct 25, 2011 5:09 am
Should be (A), here's what I did

x:y = 10a/3b = 10/3. This ,means a = b.
Similarly, y:z = 3b/7c = 3/7. This means b =c

Now, the expression is
(7x+2y+5z)/(8a+b+3c)

Numerator, when expanded becomes 70a + 6b + 35c
Denominator, is 8a + b + 3c

Since a = b = c, The ratio thus becomes 111/12

OA please?
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by MBA.Aspirant » Tue Oct 25, 2011 5:13 am
A is correct
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by neelgandham » Tue Oct 25, 2011 5:17 am
x =10a; y = 3b;z =7c
Substitute a=b=c=1, you get x=10,y=3,z=7
The expression is(7x+2y+5z)/(8a+b+3c) = (70+6+35)/(8+1+3) = 111/12 Answer : A
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by Abhishek009 » Tue Oct 25, 2011 9:26 am
MBA.Aspirant wrote:Thanks ahead
x =10a; y = 3b;z =7c

Again x : y : z = 10 : 3 : 7


So, 10a = 10 , 3b = 3 & 7c = 7


Hence , a = b = c = 1


So , x = 10 , y = 3 and z = 7

Now we have to find -

(7x+2y+5z)/(8a+b+3c)

7*10 + 2*3 + 5*7 / 8*1 + 1 + 3*1

70+6+35 / 12

111/12


So option A will be the answer...
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