What is the radius of the circle that circumscribes the triangle, measure of whose sides is 9, 40 and 41?
A. 20
B. 20.5
C. 4
D. 8
E. 45
A. 20
B. 20.5
C. 4
D. 8
E. 45
The triangle specified here is a right angled triangle (9^2 + 40^2 = 41^2).
Always remember that in a right triangle, the hypotenuse is the diameter of the circumcircle and the centre is exactly the mid point of the hypotenuse.
So, diameter here is 41 and so, radius = 41/2 = 20.5
Answer B!
