When I simply each I get:
1) -y + 3 >= 0 >= y + 3
2) y + 3 <= 0 <= -y + 3
What am I doing wrong? Since I have them saying the same thing and only B is sufficient there must be a fault in my logic.
Thanks.
What is the value of x?
This topic has expert replies
Source: Beat The GMAT — Data Sufficiency |
-
shantanu86
- Senior | Next Rank: 100 Posts
- Posts: 59
- Joined: Sun Mar 11, 2012 8:57 pm
- Location: India
- Thanked: 16 times
- Followed by:1 members
IMO its Bdlencz wrote:If y >= 0, what is the value of x?
1) |x - 3| >= y
2) |x - 3| <= -y
OA is B
Explanation-
y>=0 is given
[1] |x-3| >=y
=>case x-3 is +ve
x-3 > =y => x > 3+y.. no solution
=>case x-3 is negative => x<3
-x+3 >= y => x =< 3-y.. no solution
[2] |x-3| <= -y
Now, y is a positive number but |x-3| can not be negative.
There the equality will hold only at one point y=0.
=> x= 3.. thus this alone is sufficient.
Hence, B.
Hope it helps!!
-
neelgandham
- Community Manager
- Posts: 1060
- Joined: Fri May 13, 2011 6:46 am
- Location: Utrecht, The Netherlands
- Thanked: 318 times
- Followed by:52 members
If y >= 0, what is the value of x?
So |x-3| = 0, and x = 3
Answer B
Implies (x-3)>y or (x-3)<-y. We don't have a single value of x in this case. So, statement I is insufficient to answer the question.1) |x - 3| >= y
We know that mod of any number is greater than or equal to(>)0. We also know that y>0, So -y<0. Statement II reads |x - 3| <= -y. We already know that |x - 3|>0 and -y<0. So the only value that satisfies the condition is y = 0, and for all other values -y<0, which isn't possible according to statement II.2) |x - 3| <= -y
So |x-3| = 0, and x = 3
Answer B
Anil Gandham
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
Welcome to BEATtheGMAT | Photography | Getting Started | BTG Community rules | MBA Watch
Check out GMAT Prep Now's online course at https://www.gmatprepnow.com/
