BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Another Problem with factors and multiples

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
User avatar
Legendary Member
Posts: 2134
Joined: Mon Oct 20, 2008 11:26 pm
Thanked: 237 times
Followed by:25 members
GMAT Score:730

Re: Another Problem with factors and multiples

by logitech » Sat Jan 03, 2009 5:21 pm
Hmm,

3 or 4 = divisible 3+divisible 4 - divisible with 12 ( think like a set )

200/3 = 66 numbers

200/4 = 50 numbers

200/12 = 16 numbers

60+56 - 16 = 100

Am I right ?
LGTCH
---------------------
"DON'T LET ANYONE STEAL YOUR DREAM!"
Top
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pm
Thanked: 331 times
Followed by:11 members

by cramya » Sat Jan 03, 2009 6:10 pm
3*1(3) to 3*66(198)

So total of 66-1+1 = 66 multiples of 3 (1)

4*1(4) to 4*50(200)

50-1+1 = 50 multiples of 4 (2)

We would have double counted the common multiples of 3 and 4 i.e multiples of 12 which we need to subtract after adding (1) and (2)

12*1 to 12*16

So 16-1+1 = 16 multiples of 12

66+50-16 = 100

Choose C)
Top
Post new topic Post Reply
• Page 1 of 1