Question about Example in MGMAT Num Prop. Book

Problem Solving — algebra and arithmetic (GMAT Focus Edition)
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Hi,

I did a cursory check of the topics in this forum and I couldn't find one that addressed my question.
If I've missed it, I'd appreciate the link.

I just purchased the MGMAT Number Properties book (which has been really helpful), but when I was reviewing one of their examples on divisibility, I was still unsure of how they arrived at their solution.

The question:

If x^3 - x = p, and x is odd, is p divisible by 24?

The solution:

x(x^2 -1) => x(x+1)(x-1) => these are consecutive integers, so reorder:

(x-1) x (x+1)

The book goes on to prove that p is divisible by 24, b/c if x is odd then (x-1) & (x+1) are even.
Therefore (x-1) will be divisible by 2 b/c it is even, & (x+1) is div. by4.

I follow this logic but doesn't this assume that x is an odd integer that is greater than 1? Which I don't think the quesiton specifies.

Am I missing something?

Thanks in advance.
Last edited by srk228 on Tue Aug 17, 2010 9:12 pm, edited 1 time in total.
Source: — Quantitative Reasoning |

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by amising6 » Mon Jul 05, 2010 11:03 am
If x^3 - x = p, and x is odd, is p divisible by 24?
x(x^2-1)
x(x-1)(x+1)
9x-1),x,(x+1) this three are consecutive integer
now given x is odd so obiously odd+1 and odd -1 i.e x+1 and x-1 are even
so now let us take example of any 3 consecutive integer 2,3,4
so product of 3 consecutive integer will be divisible by 3 (rule every nth number in a number system is divisble by n)e
and it has 2 evn number so first will b divisble by 2
and second even number will be divisble by 4
so the priduct will be disible by 2*3*4=24
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by alexshv » Mon Jul 05, 2010 12:33 pm
How about easier method:

x^3-x=n*24 -> where n is integer number
x(x^2-1)=n(5^2-1)

so n=5 and answer is yes

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by Tani » Wed Jul 07, 2010 11:53 am
You are correct. X has to be odd, which the problem did mention. For x = 1 or -1, p = 0. The questions is whether 0 is divisible by 24. If you say yes, 24 goes into 0 zero times, then the statement is true for all odd integers. If you don't consider 0 divisible by 24, then the absolute value of x must be greater than one.
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by srk228 » Tue Aug 17, 2010 9:11 pm
Thank you!