Question 2 (Nov.14)

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Question 2 (Nov.14)

by bacali » Fri Nov 14, 2008 12:34 pm
The sequence a1, a2, … , a n, … is such that an = 2an-1 - x for all positive integers n ≥ 2 and for certain number x. If a5 = 99 and a3 = 27, what is the value of x?


A. 3
B. 9
C. 18
D. 36
E. 45
Source: — Problem Solving |

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by EricLien9122 » Fri Nov 14, 2008 12:50 pm
Is answer A?

A4=2(27)-x
A4=94-x

99=2(94-x)-x
99=108-2x-x
-9=-3x
x=3

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by cramya » Fri Nov 14, 2008 12:59 pm
It should be A)

Bacali,
Friendly request: Please make sure you include the signs correctly in the problem

a ^ n = 2 * a ^ (n-1) - x is a whole lot easier to read and understand what the problem is really referring to. We can figure it out but sometimes assumptions can bite u in the back when providing solutions..

Also please incldue the official answer iusing SPOILER function.

Eg: [spoiler]OA:WHATEVER THE OA IS[/spoiler]

Regards,
Cramya

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by bacali » Fri Nov 14, 2008 8:52 pm
cramya wrote:It should be A)

Bacali,
Friendly request: Please make sure you include the signs correctly in the problem

a ^ n = 2 * a ^ (n-1) - x is a whole lot easier to read and understand what the problem is really referring to. We can figure it out but sometimes assumptions can bite u in the back when providing solutions..

Also please incldue the official answer iusing SPOILER function.

Eg: [spoiler]OA:WHATEVER THE OA IS[/spoiler]

Regards,
Cramya
Hey, sorry I'll be sure to include them from now on. Thanks

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by bacali » Fri Nov 14, 2008 8:54 pm
OA is A