Numbers

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Numbers

by j_shreyans » Sun Aug 17, 2014 9:42 pm
Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28


OAE

Thanks in advancs

Shreyans
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by [email protected] » Sun Aug 17, 2014 10:46 pm
Hi j_shreyans,

This question is perfect for TESTing VALUES.

We're told that N/6 has a remainder of 4 and N/5 has a remainder of 3. We're also told that N > 30. We're asked for the remainder when N/30?

First, let's look for a pattern. I'm going to start with N/5 with a remainder of 3....

Under these conditions, N could be....8, 13, 18, 23, 28, etc. From this, we know that N MUST end in either 3 or 8.

Next, let's deal with N/6 has a remainder of 4.....

Here, N could be 10, 16, 22, 28, 34, 40, 46, 52, 58, etc.

We now have a value that satisfies ALL 3 conditions: 58

58/30 = 1r28

Final Answer: E

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by GMATGuruNY » Mon Aug 18, 2014 2:45 am
A quick lesson on remainders:
When x is divided by 5, the remainder is 3.
In other words, x is 3 more than a multiple of 5:
x = 5a + 3.

When x is divided by 7, the remainder is 4.
In other words, x is 4 more than a multiple of 7:
x = 7b + 4.

Combined, the statements above imply that when x is divided by both 5 and 7 -- in other words, when x is divided by 35 -- there will be a constant remainder R.
Put another way, x is R more than a multiple of 35:
x = 35c + R.

To determine the value of R:
Make a list of values that satisfy the first statement:
When x is divided by 5, the remainder is 3.
x = 5a + 3 = 3, 8, 13, 18...
Make a list of values that satisfy the second statement:
When x is divided by 7, the remainder is 4.
x = 7b + 4 = 4, 11, 18...
The value of R is the SMALLEST VALUE COMMON TO BOTH LISTS:
R = 18.

Putting it all together:
x = 35c + 18.

Another example:
When x is divided by 3, the remainder is 1.
x = 3a + 1 = 1, 4, 7, 10, 13...
When x is divided by 11, the remainder is 2.
x = 11b + 2 = 2, 13...

Thus, when x is divided by both 3 and 11 -- in other words, when x is divided by 33 -- the remainder will be 13 (the smallest value common to both lists).
x = 33c + 13 = 13, 46, 79...
Onto the problem at hand:
j_shreyans wrote:Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28
Make a list of values that satisfy the first condition:
Positive integer n leaves a remainder of 4 after division by 6.
n = 6a + 4 = 4, 10, 16, 22, 28...
Make a list of values that satisfy the second condition:
Positive integer n leaves a remainder of 3 after division by 5.
n = 5b + 3 = 3, 8, 13, 18, 23, 28...

Thus, when n is divided by both 6 and 5 -- in other words, when n is divided by 30 -- the remainder will be 28 (the smallest value common to both lists).
n = 30c + 28 = 28, 58, 88...
When any of the values in this list are divided by 30, the remainder is 28.

The correct answer is E.
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by Abhishek009 » Mon Aug 18, 2014 9:07 am
Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5 . If n is greater than 30, what is the remainder that n leaves after division by 30?

(A) 3
(B) 12
(C) 18
(D) 22
(E) 28

n leaves a remainder of 4 after division by 6 , so the possible values of n are -

n = { 10 , 16 , 22 , 28 , 34 , 40 , 46 , 52 , 58 ....... }

The red part must be excluded because the next part of the question states - " n is greater than 30 "

Further the question states - " a remainder of 3 after division by 5 "

So set of numbers satisfying the conditions is - { 33 , 38 , 43 , 48 , 53 , 58 }


Check the number satisfying both the conditions in 58...

We are required to find - " Remainder that n leaves after division by 30 "

The remainder is - 58/30 => 28..

So answer is (E) 28
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by GMATinsight » Mon Aug 18, 2014 10:21 am
j_shreyans wrote:Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28


OAE

Thanks in advancs

Shreyans
Alternate Solution

n leaves a remainder of 4 after division by 6
i.e. n = 6X + 4

n leaves a remainder of 3 after division by 5
i.e. n = 5Y + 3

Therefore, 5Y + 3 = 6X + 4

i.e. Y = (6X + 1)/5
The first value of X that satisfy the given equation is 4
Therefore the First value of Y = 5

Rule: The value of X differs by Coefficient of Y (5 in this case) and Value of Y differs by co-efficient of X (6 in this case) provided there is no common factor between the coefficients of X and Y except 1

and The value of n differs by the LCM of coefficients of X and Y (5 and 6 in this case)


therefore the values of X = 4, 9, 13, 17 and so on
Similarly the values of Y = 5, 11, 17, 21 and so on
Therefore,the values of n = 28, 58, 88, 118 and so on

When value of n divided by 30 remainder is always 28

Answer: Option E
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