BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Numbers

Expert replies
by j_shreyans » Sun Aug 17, 2014 9:42 pm
Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28


OAE

Thanks in advancs

Shreyans
Join the discussion
Source: — Problem Solving |

by [email protected] » Sun Aug 17, 2014 10:46 pm
Hi j_shreyans,

This question is perfect for TESTing VALUES.

We're told that N/6 has a remainder of 4 and N/5 has a remainder of 3. We're also told that N > 30. We're asked for the remainder when N/30?

First, let's look for a pattern. I'm going to start with N/5 with a remainder of 3....

Under these conditions, N could be....8, 13, 18, 23, 28, etc. From this, we know that N MUST end in either 3 or 8.

Next, let's deal with N/6 has a remainder of 4.....

Here, N could be 10, 16, 22, 28, 34, 40, 46, 52, 58, etc.

We now have a value that satisfies ALL 3 conditions: 58

58/30 = 1r28

Final Answer: E

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by GMATGuruNY » Mon Aug 18, 2014 2:45 am
A quick lesson on remainders:
When x is divided by 5, the remainder is 3.
In other words, x is 3 more than a multiple of 5:
x = 5a + 3.

When x is divided by 7, the remainder is 4.
In other words, x is 4 more than a multiple of 7:
x = 7b + 4.

Combined, the statements above imply that when x is divided by both 5 and 7 -- in other words, when x is divided by 35 -- there will be a constant remainder R.
Put another way, x is R more than a multiple of 35:
x = 35c + R.

To determine the value of R:
Make a list of values that satisfy the first statement:
When x is divided by 5, the remainder is 3.
x = 5a + 3 = 3, 8, 13, 18...
Make a list of values that satisfy the second statement:
When x is divided by 7, the remainder is 4.
x = 7b + 4 = 4, 11, 18...
The value of R is the SMALLEST VALUE COMMON TO BOTH LISTS:
R = 18.

Putting it all together:
x = 35c + 18.

Another example:
When x is divided by 3, the remainder is 1.
x = 3a + 1 = 1, 4, 7, 10, 13...
When x is divided by 11, the remainder is 2.
x = 11b + 2 = 2, 13...

Thus, when x is divided by both 3 and 11 -- in other words, when x is divided by 33 -- the remainder will be 13 (the smallest value common to both lists).
x = 33c + 13 = 13, 46, 79...
Onto the problem at hand:
j_shreyans wrote:Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28
Make a list of values that satisfy the first condition:
Positive integer n leaves a remainder of 4 after division by 6.
n = 6a + 4 = 4, 10, 16, 22, 28...
Make a list of values that satisfy the second condition:
Positive integer n leaves a remainder of 3 after division by 5.
n = 5b + 3 = 3, 8, 13, 18, 23, 28...

Thus, when n is divided by both 6 and 5 -- in other words, when n is divided by 30 -- the remainder will be 28 (the smallest value common to both lists).
n = 30c + 28 = 28, 58, 88...
When any of the values in this list are divided by 30, the remainder is 28.

The correct answer is E.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Abhishek009 » Mon Aug 18, 2014 9:07 am
Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5 . If n is greater than 30, what is the remainder that n leaves after division by 30?

(A) 3
(B) 12
(C) 18
(D) 22
(E) 28

n leaves a remainder of 4 after division by 6 , so the possible values of n are -

n = { 10 , 16 , 22 , 28 , 34 , 40 , 46 , 52 , 58 ....... }

The red part must be excluded because the next part of the question states - " n is greater than 30 "

Further the question states - " a remainder of 3 after division by 5 "

So set of numbers satisfying the conditions is - { 33 , 38 , 43 , 48 , 53 , 58 }


Check the number satisfying both the conditions in 58...

We are required to find - " Remainder that n leaves after division by 30 "

The remainder is - 58/30 => 28..

So answer is (E) 28
Abhishek
Join the discussion

by GMATinsight » Mon Aug 18, 2014 10:21 am
j_shreyans wrote:Hi Guys ,

Pls help me out with the below .

Positive integer n leaves a remainder of 4 after division by 6 and a remainder of 3 after division by 5. If n is greater than 30, what is the remainder that n leaves after division by 30?
(A) 3
(B) 12
(C) 18
(D) 22
(E) 28


OAE

Thanks in advancs

Shreyans
Alternate Solution

n leaves a remainder of 4 after division by 6
i.e. n = 6X + 4

n leaves a remainder of 3 after division by 5
i.e. n = 5Y + 3

Therefore, 5Y + 3 = 6X + 4

i.e. Y = (6X + 1)/5
The first value of X that satisfy the given equation is 4
Therefore the First value of Y = 5

Rule: The value of X differs by Coefficient of Y (5 in this case) and Value of Y differs by co-efficient of X (6 in this case) provided there is no common factor between the coefficients of X and Y except 1

and The value of n differs by the LCM of coefficients of X and Y (5 and 6 in this case)


therefore the values of X = 4, 9, 13, 17 and so on
Similarly the values of Y = 5, 11, 17, 21 and so on
Therefore,the values of n = 28, 58, 88, 118 and so on

When value of n divided by 30 remainder is always 28

Answer: Option E
"GMATinsight"Bhoopendra Singh & Sushma Jha
Most Comprehensive and Affordable Video Course 2000+ CONCEPT Videos and Video Solutions
Whatsapp/Mobile: +91-9999687183 l [email protected]
Contact for One-on-One FREE ONLINE DEMO Class Call/e-mail
Most Efficient and affordable One-On-One Private tutoring fee - US$40-50 per hour
Join the discussion