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Quadratic Equation

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by harshavardhanc » Thu Mar 18, 2010 2:17 am
chdn20 wrote:Given that (d/4)+(8/d)+3=0, what is d?

Could someone factor using 4d and show there steps? I'm trying to verify my answer but keep coming up with different solutions..


Thanks
(d/4)+(8/d)+3=0

=> d^2 + 32 + 12d = 0
=> (d+8)(d+4) = 0
=> d= -8 or -4

:)
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Harsha
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by chdn20 » Thu Mar 18, 2010 3:43 am
Thanks for explaining but could you explain how you got d^2 + 32 + 12d = 0 ??

Thanks again.
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by harshavardhanc » Thu Mar 18, 2010 4:05 am
chdn20 wrote:Thanks for explaining but could you explain how you got d^2 + 32 + 12d = 0 ??

Thanks again.
ok. the fractions that we have are: (d/4), (8/d), and (3/1).

The LCM is 4d. So, multiply (d/4)+(8/d)+3=0 by 4d.

You will get, d^2 + 32 + 12d = 0

hope it is clear now. :)
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Harsha
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