Is |x -y| > |x| + |y|?
(1) y < x
(2) xy < 0
(1) y < x
(2) xy < 0
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Dear abhasjhaabhasjha wrote:Is |x -y| > |x| + |y|?
(1) y < x
(2) xy < 0
For any real values of x and y the above inequality is never true. Purpose lost, we need no further info. It cannot be a GMAT problem for sure. DS died in the stem only!abhasjha wrote:Is |x -y| > |x| + |y|?
(1) y < x
(2) xy < 0
One approach is to plot the distances on a NUMBER LINE.Is |x-y| > |x| - |y| ?
1) y < x
2) xy < 0



GMATGuruNY wrote:I suspect that the question stem should read as follows:
One approach is to plot the distances on a NUMBER LINE.Is |x-y| > |x| - |y| ?
1) y < x
2) xy < 0
|x|= the distance between x and 0 = the RED segment on the number lines below.
|y| = the distance between y and 0 = the BLUE segment on the number lines below.
|x-y| = the distance BETWEEN X AND Y.
Statement 1: y<x
Case 1:
|x| - |y| = RED - BLUE.
|x-y| = RED - BLUE.
Thus, |x-y| = |x| - |y|.
Case 2:
|x| - |y| = RED - BLUE.
|x-y| = RED + BLUE.
Thus, |x-y| > |x| - |y|.
INSUFFICIENT.
Statement 2: xy<0
Since x and y have different signs, they are on OPPOSITE SIDES OF 0.
In each case:
|x| - |y| = RED - BLUE.
|x-y| = RED + BLUE.
Thus, |x-y| > |x| - |y|.
SUFFICIENT.
The correct answer is B.
Statement 2 requires that xy < 0, so we cannot consider x=5 and y=3.[email protected] wrote:Hey Mitch,
statement 2:
Now of we place the same values in |x|-|y|=|5|-|3|=2 aren't we getting the same value?
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