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Q. from Integers- Interpretation of Q&A please.

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by shimmer » Mon Jul 18, 2011 5:13 am
Hi,

I realize that there are a couple of posts around this question on the forum already. However, I'm having trouble with not just understanding the solution (in the book and the ones on the forum) but with interpreting the question as well.

"A wire is cut into 3 equal parts. The resulting segments are then cut into 4,6 and 8 equal parts respectively. If each of the resulting segments has an integer length, what is the minimum length of the wire? "

- Initially I understood it as the wire is cut into 1/3+1/3+1/3. Followed by
-piece one= 1/3*1/4
-piece two= 1/3*1/6
-piece three= 1/3*1/8

Therefore making the smallest piece 1/24 of the original. I understand this isn't an integer (and the question in the book doesn't have answer choices) but if 24 was listed as an answer option that's what I would have picked.

From the answer explanation given in the book and on the forum so far (neither of which I understand yet), I'm on an entirely wrong track.

Can someone please please break this down for me? Thanks a lot!

PS: Underlining and bold-ing the parts of the question I think I'm misunderstanding.
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Source: — Problem Solving |

by amit2k9 » Mon Jul 18, 2011 6:26 am
lcm of 3,4,6 and 8 is 24.

since each part has to be divisible by 4,6 and 8

meaning

24 = 2*3*4, hence each part must be of length 24.

thus 24*3 = 72. smallest part of 24/8 = 3.

hence 3/72 = 1/24 is the smallest part.
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by kevincanspain » Mon Jul 18, 2011 7:53 am
shimmer wrote:Hi,

I realize that there are a couple of posts around this question on the forum already. However, I'm having trouble with not just understanding the solution (in the book and the ones on the forum) but with interpreting the question as well.

"A wire is cut into 3 equal parts. The resulting segments are then cut into 4,6 and 8 equal parts respectively. If each of the resulting segments has an integer length, what is the minimum length of the wire? "

- Initially I understood it as the wire is cut into 1/3+1/3+1/3. Followed by
-piece one= 1/3*1/4
-piece two= 1/3*1/6
-piece three= 1/3*1/8

Therefore making the smallest piece 1/24 of the original. I understand this isn't an integer (and the question in the book doesn't have answer choices) but if 24 was listed as an answer option that's what I would have picked.

From the answer explanation given in the book and on the forum so far (neither of which I understand yet), I'm on an entirely wrong track.

Can someone please please break this down for me? Thanks a lot!

PS: Underlining and bold-ing the parts of the question I think I'm misunderstanding.
Let's say that that the original wire has a length of x units. It is cut into 3 pieces of length x/3.
The first piece is divided into 4 pieces of length x/12, the second into 6 pieces of length x/18, and the third into 8 pieces of x/24. Thus x must be a multiple of 12, 18 and 24. 72 is the smallest such integer
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