BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Q.65 Problem Solving GMAT Review 13th Edition

Expert replies
by Priyaranjan » Sat Mar 14, 2015 3:32 am

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty

The average distance between the Sun and a certain planet is approximately 23*10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometres? (1 Kilometre is approximately 3.9*10^4 inches)

A) 7.1*10^8
B) 5.9*10^9
C) 1.6*10^10
D) 1.6*10^11
E) 5.9*10^11

Answer is B. As per the OG answer description, it took the approximate value of 23/39 as 2/4 and derived at a value of 5*10^9.But, what will be the answer if the approximate value of 23/39 will be taken as 2/3?
Join the discussion
Source: — Problem Solving |

by GMATGuruNY » Sat Mar 14, 2015 4:45 am
The prompt as posted has a typo.
It should read as follows:
The average distance between the Sun and a certain
planet is approximately 2.3 X 10^14 inches. Which of the
following is closest to the average distance between
the Sun and the planet, in kilometers? (1 kilometer is
approximately 3.9 X 10^4 inches.)

(A) 7.1 X 10^8
(B) 5.9 X 10^9
(C) 1.6 X 10^10
(D) 1.6 X 10^11
(E) 5.9 X 10^11
As for your question:
Priyaranjan wrote:what will be the answer if the approximate value of 23/39 will be taken as 2/3?
(2.3 * 10¹�)/(3.9 * 10�) ≈ 2/3 * 10¹� ≈ 0.66 * 10¹� = 6.6 * 10�.

The closest answer choice is B.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by Brent@GMATPrepNow » Sat Mar 14, 2015 11:10 am
Priyaranjan wrote:The average distance between the Sun and a certain planet is approximately 23*10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometres? (1 Kilometre is approximately 3.9*10^4 inches)

A) 7.1 x 10^8
B) 5.9 x 10^9
C) 1.6 x 10^10
D) 1.6 x 10^11
E) 5.9 x 10^11
We can solve the question using equivalent ratios.
We're comparing kilometers and inches, so the ratio is kilometers/inches

1 Kilometre is approximately 3.9 x 10^4 inches
So, we have the ratio: 1/(3.9 x 10^4)

We're told the number of inches to the sun (2.3 X 10^14) and we must find the number of equivalent kilometers.
Let d = the number of kilometers.
So, we have the ratio: 1/(2.3 X 10^14)

We can now write: 1/(3.9 x 10^4) = d/(2.3 X 10^14)
To solve for d, first cross multiply to get: d(3.9 x 10^4) = 1(2.3 X 10^14)
Solve for d to get: d = (2.3 X 10^14)/(3.9 x 10^4)
d = [2.3/3.9][(10^14)/(10^4)]
d = [0.59][10^10]
Check the answer choices...not there.
To get our response into the proper format, rewrite 0.59 as 5.9 x 10^-1 to get...
d = [5.9 x 10^-1][10^10]
d = [spoiler]5.9 x 10^9[/spoiler]
Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by misterholmes » Mon Mar 16, 2015 1:41 am
Priyaranjan wrote:The average distance between the Sun and a certain planet is approximately 23*10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometres? (1 Kilometre is approximately 3.9*10^4 inches)

A) 7.1*10^8
B) 5.9*10^9
C) 1.6*10^10
D) 1.6*10^11
E) 5.9*10^11

Answer is B. As per the OG answer description, it took the approximate value of 23/39 as 2/4 and derived at a value of 5*10^9.But, what will be the answer if the approximate value of 23/39 will be taken as 2/3?
Priyaranjan,

Part 1: It's fine to take the approximation as 2/4, provided you keep in mind that it's less than 23/39. Also fine to estimate at 2/3, keeping in mind that it's more than 23/39. An estimate can be paired with a direction to improve eliminations, so this is a good habit to practice.

Part 2: Assuming the estimate 2/3, the result as 6.6x10^9, and this is greater than the true value.

Regards,
Mike
www.google.com/+MikeMiagi
www.gmatdojo.com
Mindfulness, Concentration, Insight
Join the discussion

by Scott@TargetTestPrep » Tue Jun 30, 2015 11:45 am
Priyaranjan wrote:The average distance between the Sun and a certain planet is approximately 23*10^14 inches. Which of the following is closest to the average distance between the Sun and the planet, in kilometres? (1 Kilometre is approximately 3.9*10^4 inches)

A) 7.1*10^8
B) 5.9*10^9
C) 1.6*10^10
D) 1.6*10^11
E) 5.9*10^11

Answer is B. As per the OG answer description, it took the approximate value of 23/39 as 2/4 and derived at a value of 5*10^9.But, what will be the answer if the approximate value of 23/39 will be taken as 2/3?
Solution:

This problem is a unit conversion with an added twist of scientific notation. We need to convert 2.3 x 10^14 inches to KILOMETERS. We are given that 1 kilometer is approximately 3.9 X 10^4 inches. We also should recognize that we are being asked which of the following is CLOSEST to the average distance between the Sun and the planet, in kilometers. Because we are being asked for an approximation, we can use some estimation here.

To convert 2.3 x 10^14 inches to kilometers, we need to multiply 2.3 x 10^14 inches by the ratio of:

1 km/(3.9 x 10^4 inches)

However, before doing this multiplication, it will make things easier by "cleaning up" each scientific notation expression. Let's start with 2.3 x 10^14 inches.

2.3 x 10^14 inches

is equivalent to

23 x 10^13 inches

Notice that because we turn 2.3 into 23, or move the decimal one place to the right, we have to then turn 10^14 into 10^13, or move the decimal one place to the LEFT to counterbalance the fact that we've moved the decimal one place to the right for 2.3.

Next we can adjust 3.9 x 10^4 inches. However, we can simply round this value up to 4 x 10^4 inches because the question only asks for the closest answer.

Since we've rounded 3.9 up to 4, let's round 23 up to 24 also. That is, we are converting 24 x 10^13 inches into kilometers given that 1 km is approximately 4 x 10^4 inches:

(24 x 10^13 inches) x 1 km/(4 x 10^4 inches)

(24 x 10^13)/(4 x 10^4) km

We can break this work up into two separate calculations:

1) 24/4 = 6

2) 10^13/10^4 = 10^9

Thus, our answer is about 6 x 10^9 km.

We see that the closest answer is 5.9 x 10^9.

Answer: B

Scott Woodbury-Stewart
Founder and CEO
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews

ImageImage
Join the discussion

by metalbar55 » Sun Oct 20, 2019 7:42 pm
How did everyone know that it was 2.3x10^14 inches and not 24x10^14? In the daily question of the day email as well as the question initially posted in the thread, it shows 24x10^14 (at least for me), which is why I chose answer E.
Join the discussion

Hi All,

Here, we’re told that the distance between the Sun and a planet is 2.3 x 10^14 INCHES. We’re asked which answer is closest to that distance in KILOMETERS. This is just a ‘unit conversion’ question (and the prompt tells us that 1 km = 3.9 x 10^4 inches), so we just have to keep track of the decimal points and the ‘powers of 10’…

Since 2.3 is less than 3.9, we can make the division a little easier to “look at” by ‘rewriting’ the first piece of information by distributing one of the 10s. This gives us:

23 x 10^13 inches

Now, when we divide this by 3.9 x 10^4, we can think in terms of how many times 3.9 divides into 23. Rounding 3.9 “up” to 4, we can see that it’s a little less than 6 times. Looking at the answer choices, we can clearly see that 5.9 is the best match. The last step is to divide 10^13 by 10^4 – and that’s fairly easy: we “subtract” the exponents – and that gives us 10^9.

Final Answer: B

GMAT Assassins aren’t born, they’re made,
Rich
Contact Rich at [email protected]
Image
Join the discussion