PS1000 Sec7 #20

This topic has expert replies
Master | Next Rank: 500 Posts
Posts: 125
Joined: Mon Dec 15, 2008 9:24 pm

PS1000 Sec7 #20

by joyseychow » Sun Apr 19, 2009 8:08 pm
This is simple but I can't seem to get around this one. Especially with "determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price". Appreciate if someone could explain.


A merchant purchased a jacket for $60 and then determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price. During a sale, the merchant discounted the selling price by 20 percent and sold the jacket. What was the merchant’s gross profit on this sale?
(A) $0
(B) $3
(C) $4
(D) $12
(E) $15

Master | Next Rank: 500 Posts
Posts: 322
Joined: Fri Mar 27, 2009 3:56 pm
Thanked: 24 times
GMAT Score:710

by mike22629 » Mon Apr 20, 2009 11:04 am
Use algebra to solve this problem:

A 25% markup is equivalent to multiplying the original price by 5/4

A 20% discount is equivalent to multiplying price by 4/5

Hence 60(5/4)(4/5) = 60

60 - 60 = 0 profit

IMO A

Senior | Next Rank: 100 Posts
Posts: 60
Joined: Thu Feb 26, 2009 12:50 pm
Location: Chicago
Thanked: 3 times

by rossmj » Thu Apr 23, 2009 10:18 am
C.

determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price MEANS:

60+(1/4)S=S--->60=(3/4)S--->S=80

20% off 80=64--->64-60=4

Master | Next Rank: 500 Posts
Posts: 125
Joined: Mon Dec 15, 2008 9:24 pm

by joyseychow » Sun Apr 26, 2009 11:16 pm
rossmj wrote:C.

determined a selling price that equaled the purchase price of the jacket plus a markup that was 25 percent of the selling price MEANS:

60+(1/4)S=S--->60=(3/4)S--->S=80

20% off 80=64--->64-60=4
Thanks! OA is indeed C.