BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

PS1000 Sec1 Q10

Expert replies
by joyseychow » Wed Feb 11, 2009 4:51 am
Is there a faster way of calculating this other than listing it by rows? Maybe a formula?

What is the total number of integers between 100 and 200 that are divisible
by 3?
(A) 33
(B) 32
(C) 31
(D) 30
(E) 29
Join the discussion
Source: — Problem Solving |

by mals24 » Wed Feb 11, 2009 5:10 am
Well you can calculate this in 2 ways:

1: 100-200

The First Number divisible by 3 in this range is 102 and the last is 198

(A number is divisible by 3 if the sum of the digits is a multiple of 3)

102/3 = 34
198/3 = 66

So number of digits between 34-66 (inclusive) = (66-34) + 1 = 33

2: 200/3 = 66.67
So from 1-200 there are 66.67 numbers that are divisible by 3

100/3 = 33.33
So from 1-100 there are 33.33 numbers that are divisible by 3

Hence 100-200 = 66.67-33.33 = 33 approx
Join the discussion

by ellexay » Wed Feb 11, 2009 5:44 pm
I don't know if this is just coincidence, but I actually got the answer this way -

198/3 = 66 (i chose 198 because it's the first number counting down from 200 that's divisible by 3)

66/2 = 33 (i figure that half of those 66 numbers will be divisible by 3).

Can someone verify whether this is a coincidence?
Join the discussion

Re: PS1000 Sec1 Q10

by x2suresh » Wed Feb 11, 2009 8:56 pm
joyseychow wrote:Is there a faster way of calculating this other than listing it by rows? Maybe a formula?

What is the total number of integers between 100 and 200 that are divisible
by 3?
(A) 33
(B) 32
(C) 31
(D) 30
(E) 29
smallest integers that is divisiable by 3 in the range 100 and 200
= 3
largest integer that is divisble by 3 in the range 100 and 200
= 198

Anser = (198-3)/3 +1(to include 3 smallest integer) = 65+1 =66.
Join the discussion

by billzhao » Wed Feb 11, 2009 9:16 pm
Using methods of sequence.

A1=102, An=198 and d=3

now we need to find n:

knowing that: An=A1+(n-1)*d

we have: 198=102+(n-1)*3, we can get that n=33

Answer is (A)
Yiliang
Join the discussion

Re: PS1000 Sec1 Q10

by x2suresh » Wed Feb 11, 2009 9:50 pm
x2suresh wrote:
joyseychow wrote:Is there a faster way of calculating this other than listing it by rows? Maybe a formula?

What is the total number of integers between 100 and 200 that are divisible
by 3?
(A) 33
(B) 32
(C) 31
(D) 30
(E) 29
smallest integers that is divisiable by 3 in the range 100 and 200
= 102
largest integer that is divisble by 3 in the range 100 and 200
= 198

Anser = (198-102)/3 +1(to include 3 smallest integer) = 32+1 =33.
Join the discussion