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by ri2007 » Sun Nov 18, 2007 5:34 pm
ans should be C

1) n is divisible by 6 so n is a multiple of 4, but we lack a 2 to make it a factor of 12
2) n is divisible of 4, so n is a multiple of 4, but we lack a 3

together n is a multiple of 3 and 4 so it is divisible by 12
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by aimhigh715 » Sun Nov 18, 2007 11:08 pm
Should be C) too

1) N/6 = integer meaning 6 is a factor / no remainder for division.

N could be 12 (which works with 12/12... but!) could also be 18 (which doesn't divide into 12 fully)

factors (1,2,3,6)

Not Sufficient

2) N/4
N could be 4, 8, 12, 16. Only 12 divides into 12.

factors (1,2,2,4)

Not sufficient.

Consider C/E

N/6 factor of 6 (1,2,3,6)
N/4 factor of 4 (1,2,2,4)

12 is (1,2,3,4,6,12) which is part of that # group.

Sufficient. C)
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