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by govind_raj_76 » Sun May 02, 2010 11:08 am
How many four-digit numbers, that are divisible 5, are there that do not contain the digits 4 or 8 and none of the digits are repeated ?

A) 390

B) 360

C) 330

D) 310

E) 180
Govind
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by iamseer » Sun May 02, 2010 11:31 am
IMO A

we have to form a-digit number from 1,2,3,5,6,7,9,0
No numbers can be repeated and number must be divisible by 5

So, last digit is either 0 or 5

Last Digit 5 -
First digit can't be 0
first digit can be selected from 1,2,3,6,7,9 = 6 ways
second digit can be selected again in 5+1 ways (now we can use the 0)
third digit can be selected in 5 ways
therefore 6*6*5

Similarly,
Last Digit 0
7*6*5

Total 5*6*(6+7)=390

HTH
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