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GMAT PREP combination pblm

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Senior | Next Rank: 100 Posts
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by rishi235 » Tue Aug 19, 2008 10:39 am
Hi this is how i worked on it

A) 3 notepads of the same size & same color
Lets consider a stick of 1st size
The figure 3 is just to add to the confusion
1 size notepad => 4 colors...Hence 4 different types=> 4 packages (for 1 type of notepad)

B) 3 notepads of the same size & different colors
Consider only 1 type of notepad
Here we need the number "3"...
v need 3 different colors....we have total 4 colors...
=> 4C3 = 4 packages (for 1 type of notepad)

Hence for the 2 types of notepads
2(4+4) = 16...

If theres a better method...pls share
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Senior | Next Rank: 100 Posts
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by ramyaravindran » Tue Aug 19, 2008 10:52 am
Let's assume that the 2 different sizes are Size 1 and Size 2. Size 1 and Size 2 are both available in Blue, Green, Yellow and Pink. (i.e)

1Blue,1Green,1Yellow,1Pink,2Blue,2Green,2Yellow and 2Pink.

We are given that the above are packaged such that there are 3 notepads of same size and color or there are 3 notepads of same size and 3 different colors.

3 notepads of Same Size and color can be package in 8 ways (Say 3 notepads of Size 1 blue, 3 notepads of Size 1 Green ...etc)

3 notepads of same size and 3 different colors can be packaged in 4C3 ways for Size 1([1Blue,1Green,1Yellow],[1Blue,1Yellow,1Pink],[1Green,1Yellow,1Pink],[1Blue,1Green,1Pink])

Similarly it is 4C3 ways for Size 2.

This comes to a total of 8+4C3+4C3 ways = 16
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