BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

GMAT PREP combination pblm

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Source: — Problem Solving |
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Sat Aug 02, 2008 10:05 pm
Thanked: 5 times

by rishi235 » Tue Aug 19, 2008 10:39 am
Hi this is how i worked on it

A) 3 notepads of the same size & same color
Lets consider a stick of 1st size
The figure 3 is just to add to the confusion
1 size notepad => 4 colors...Hence 4 different types=> 4 packages (for 1 type of notepad)

B) 3 notepads of the same size & different colors
Consider only 1 type of notepad
Here we need the number "3"...
v need 3 different colors....we have total 4 colors...
=> 4C3 = 4 packages (for 1 type of notepad)

Hence for the 2 types of notepads
2(4+4) = 16...

If theres a better method...pls share
Top
Senior | Next Rank: 100 Posts
Posts: 49
Joined: Mon Apr 28, 2008 5:33 am
Thanked: 2 times

by ramyaravindran » Tue Aug 19, 2008 10:52 am
Let's assume that the 2 different sizes are Size 1 and Size 2. Size 1 and Size 2 are both available in Blue, Green, Yellow and Pink. (i.e)

1Blue,1Green,1Yellow,1Pink,2Blue,2Green,2Yellow and 2Pink.

We are given that the above are packaged such that there are 3 notepads of same size and color or there are 3 notepads of same size and 3 different colors.

3 notepads of Same Size and color can be package in 8 ways (Say 3 notepads of Size 1 blue, 3 notepads of Size 1 Green ...etc)

3 notepads of same size and 3 different colors can be packaged in 4C3 ways for Size 1([1Blue,1Green,1Yellow],[1Blue,1Yellow,1Pink],[1Green,1Yellow,1Pink],[1Blue,1Green,1Pink])

Similarly it is 4C3 ways for Size 2.

This comes to a total of 8+4C3+4C3 ways = 16
Top
Post new topic Post Reply
• Page 1 of 1