BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem
TTP OnDemand GMAT Video Course
Featured Course

Target Test Prep GMAT OnDemand

Scott Woodbury-Stewart’s private virtual classroom — 400 hours of master-class video lessons for the GMAT Focus Edition.

  • 715+ score guarantee — highest in the industry (99th percentile)
  • 52 chapters · 1,500+ lessons · 4,000+ practice questions
  • 400 hours of video · 1,500+ instructor-led HD smartboard lessons
  • 300,000+ students accepted to Harvard, Stanford, Wharton, Booth & Sloan & more
  • 24/7 live support + weekly Zoom office hours with GMAT instructors
  • TTP AI Assist — 24/7 AI-powered virtual tutor for instant help
  • 1,200+ flashcards + AI-powered study assistant & daily calendar
  • OnDemand, LiveTeach & GMAT Bootcamp formats available
  • Also: GRE, SAT Math & Executive Assessment courses
  • MBA Admissions Consulting now available
  • 🏆 2025 EdTech Breakthrough Award: Test Prep Solution Provider of the Year
  • 200,000+ students served
  • 5-day free trial — $0 to start, no auto-billing, cancel anytime
★★★★★ 5.0 (559 reviews)
130-pt guarantee
$0 to start then $127/mo
Start Free 5-Day Trial Read 559 Reviews →

Try this one

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
User avatar
Senior | Next Rank: 100 Posts
Posts: 79
Joined: Thu Oct 23, 2008 9:28 am
Location: Canada
Thanked: 1 times
GMAT Score:700
by adilka » Mon Jan 12, 2009 8:36 pm
AB + CD = AAA, where AB and CD are two-digit numbers and AAA is a three digit number; A, B, C, and D are distinct positive integers. In the addition problem above, what is the value of C?

(A) 1

(B) 3

(C) 7

(D) 9

(E) Cannot be determined
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Master | Next Rank: 500 Posts
Posts: 259
Joined: Thu Jan 18, 2007 8:30 pm
Thanked: 16 times

by amitabhprasad » Mon Jan 12, 2009 8:47 pm
I am getting "9"
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Wed Jan 07, 2009 1:56 pm
Thanked: 12 times
GMAT Score:750

by arzanr » Mon Jan 12, 2009 8:48 pm
Ans would be E.

AAA has to be 111 because you cannot get 222 or above by adding two 2digit numbers.

Therefore, 13 + 98 = 111 and 17 + 94 = 111. As a result C cannot be determined.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Mon Jan 12, 2009 8:52 pm
17
94

111

So c is 9 (1 will be the carry over so c will always be 9)
Last edited by cramya on Mon Jan 12, 2009 8:54 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Mon Jan 12, 2009 8:53 pm
Azanr,
Would c not always be 9 in both ur cases?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 60
Joined: Wed Jan 07, 2009 1:56 pm
Thanked: 12 times
GMAT Score:750

by arzanr » Mon Jan 12, 2009 8:55 pm
cramya wrote:Azanr,
Would c not always be 9 in both ur cases?
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary :)
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2467
Joined: Thu Aug 28, 2008 6:14 pmFollowed by: 11 members
Thanked: 331 times

by cramya » Mon Jan 12, 2009 9:00 pm
Haha you're right.. I mixed up C and D.. I just got done with doing a full timed practice test so a little weary

It happens; nice solution though!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Senior | Next Rank: 100 Posts
Posts: 79
Joined: Thu Oct 23, 2008 9:28 am
Location: Canada
Thanked: 1 times
GMAT Score:700

by adilka » Mon Jan 12, 2009 10:18 pm
Correct folks. OA is 9, D
Last edited by adilka on Tue Jan 13, 2009 1:15 pm, edited 1 time in total.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 73
Joined: Wed Jan 07, 2009 1:00 pm
Location: Tampa, FL
Thanked: 9 times
GMAT Score:630

by Mr2Bits » Tue Jan 13, 2009 8:21 am
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 424
Joined: Sun Dec 07, 2008 5:15 pm
Location: Sydney
Thanked: 12 times

by piyush_nitt » Wed Jan 14, 2009 4:17 am
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 73
Joined: Wed Jan 07, 2009 1:00 pm
Location: Tampa, FL
Thanked: 9 times
GMAT Score:630

by Mr2Bits » Wed Jan 14, 2009 7:42 am
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 424
Joined: Sun Dec 07, 2008 5:15 pm
Location: Sydney
Thanked: 12 times

by piyush_nitt » Wed Jan 14, 2009 7:56 pm
Mr2Bits wrote:
piyush_nitt wrote:
Mr2Bits wrote:
adilka wrote:Correct folks. OA is 9, E
Answer is 9 (D) was no other value satisfies AAA having to equal 111.

How about

84 + 27

74 + 37

Above eqn , equates to 111


Got it ..Thanks !

Missed that part.

Anything wrong in my logic?
Yes your logic is flawed becuase in your case you would be needing to satisfy 888 (AB=84(A=8)) or 777(AB=74(A=7))

The question is asking for two, two digit postive integers when added together equal a 3 digit positve integer where all three digits are the same(this is your A value). Only option is AAA= 111
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1