x,y>0 .If xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
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oldheaven wrote:x,y>0 .If xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
neelgandham wrote:Please don't shower bats at me for solving this question, this way !
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
There is an algebraic solution, but this still seems to be a very unGMATlike question in that it only has four answer choices and is extremely difficult. I think that people who are only interested in the GMAT would be wise to skip this question.neelgandham wrote:Thanks Tomada ! and I am sure that you need not have knowledge of calculus for the GMAT(Knowing some formulae doesn't hurt, and sometimes helps as in this case). I am sure we can solve this in a better(read using algebra) way.So, let us wait for the experts to reply!
Okay I just read some of your other posts explaining the source of these questions. You say it's some kind of GMAT-like test in Iran? If you post a non-standard GMAT question, I think it's important to note the source so that other people don't get worried if it seems way too hard for them.oldheaven wrote:x,y>0 .If xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
and to be more precise with calculus ...neelgandham wrote:Please don't shower bats at me for solving this question, this way !
If x,y>0, xy=6 then what is the minimum of 3x+5y ?
1)6sqrt(10)
2)sqrt(30)
3)2sqrt(10)
4)3aqrt(6)
xy = 6, Implies y =6/x
The expression 3x + 5y = 3x + (30/x) = (3x^2 + 30)/x
Maximum/Minimum value of a function f(x) can be found by initially finding the value of x that satisfies the equation f '(x) = 0 (where f '(x) is the derivative of f(x)) and then substitution the value of x in the function f(x).
f(x) = (3x^2 + 30)/x
f'(x) = (3x^2 - 30)/x^2 = 0 ; x =√10 and the derivative of f'(x)>0(which tells us that f(x) at x =√10 is minimum)
The expression 3x + 5y = 3x + (30/x) = 3√10 +(30/√10) = 6√10 A
Derivative formulae -> https://math.about.com/library/weekly/aa021003a.htm- I used rule #9
Thanks Brent your post gave some relief to me.Brent@GMATPrepNow wrote:Since this thread is still alive and kicking, I want to make it clear that the question is out of scope.
Cheers,
Brent
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