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Problems on sequence Part III (for bacali and others)

Expert replies
Source: — Problem Solving |

austin wrote:1/2+1/4+1/8+...+1/512=?
A.0<S<1/2
B.1/2<S<1
C.1<S<3/2
D. 3/2<S<2
E. 2<S<5/2
Let's play everyone's favourite Thanksgiving game, "spot the pattern" (boo.. no turkey emoticon)!

1/2 + 1/4 = 3/4
3/4 + 1/8 = 7/8
7/8 + 1/16 = 15/16

As we progress, we're getting closer and closer to 1, but we're never actually going to get there. So, the sum of the sequence will be less than 1, but more than the 1/2 we start with: choose (B).

If anyone actually cares about the math, the generic formula for this particular sequence is:

Sum(first n terms) = (2^n - 1)/2^n

So, if we have 9 terms (512 = 2^9), the sum is:

(2^9 - 1)/2^9 = 511/512
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by cramya » Thu Nov 27, 2008 5:00 pm
Stuart,

On a different note could u please look in to https://www.beatthegmat.com/mod-problem- ... 23680.html

and provide your thoughts.
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