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problem to solve

This topic has 2 expert replies and 2 member replies

problem to solve

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Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5

A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5


what would be the right way to go about this ?

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Master | Next Rank: 500 Posts Default Avatar
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27 Feb 2007
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Simplify it as
a+a+b+b+b
where a=2^5 and b=3^5

So the expression is 2a+3b = 2*2^5+3*3^5 = 2^6+3^6.

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Senior | Next Rank: 100 Posts Default Avatar
Joined
14 Mar 2007
Posted:
38 messages
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ohhhhhhhhhh... thanks man... very good explanation.

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Atult718 wrote:
Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5

A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5
2^5+2^5+3^5+3^5+3^5

2^5(1 + 1) + 3^5(1 + 1 + 1)

2^5(2) + 3^5(3)

2^6 + 3^6

Answer: C

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GMAT/MBA Expert

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Atult718 wrote:
Q: Which of the following is equal to the value of
2^5+2^5+3^5+3^5+3^5

A) 5^6
B) 13^5
C) 2^6+3^6
D) 2^7+3^8
E) 4^5+9^5
What we really have here is an algebra question requiring us to combine like terms.

First, notice that K + K = 2K
Using the same logic, 2^5 + 2^5 = 2(2^5) = (2^1)(2^5) = 2^6

Similarly, notice that M + M + M = 3M
Using the same logic, 3^5 + 3^5 + 3^5 = 3(3^5) = (3^1)(3^5) = 3^6

So, 2^5 + 2^5 + 3^5 + 3^5 + 3^5 = 2^6 + 3^6

Answer: C

Cheers,
Brent

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