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## problem

This topic has 2 member replies
iamtrying Newbie | Next Rank: 10 Posts
Joined
21 Aug 2006
Posted:
8 messages

#### problem

Tue Oct 17, 2006 9:27 am
This problem appears to be very simple, i guess i am having a bad day!!!

There were 36.000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45.000
(B) 360.000
(C) 364.500
(D) 392.000
(E) 396.900

anandsebastin Junior | Next Rank: 30 Posts
Joined
13 Oct 2006
Posted:
10 messages
Wed Oct 18, 2006 6:31 pm
iamtrying wrote:
This problem appears to be very simple, i guess i am having a bad day!!!

There were 36.000 hardback copies of a certain novel sold before the paperback version was issued. From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. If a total of 441.000 copies of the novel were sold in all, how many paperback copies were sold?
(A) 45.000
(B) 360.000
(C) 364.500
(D) 392.000
(E) 396.900
C

P = 9H

P+H+36000 = 441000
10H = 405000
9H = P = 405000*9/10 = 364,500

countingdolls Junior | Next Rank: 30 Posts
Joined
02 Oct 2006
Posted:
13 messages
Tue Oct 17, 2006 10:20 am
hi,

problem says --
From the time the first paperback copy was sold until the last copy of the novel was sold. 9 times as many paperback copies as hardback copies were sold. So if 'n' is no of hardbacks sold since first paperback copy was sold, then 9n is the no of paperbacks sold.

total sold=441000
copies sold since first paperback was sold = 441000 - 36000 = 405000
this no equals = n + 9n = 10n
so, no of paperbacks = 9/10 * 405000

ans = (C)

hope its clear

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