BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Difficult Math Problem #92 - Sets

This topic has expert replies
Post new topic Post Reply
Previous Topic Next Topic
Master | Next Rank: 500 Posts
Posts: 354
Joined: Tue Jun 27, 2006 9:20 pm
Thanked: 11 times
Followed by:5 members

Difficult Math Problem #92 - Sets

by 800guy » Wed Jan 31, 2007 9:10 pm
OA coming after some people provide answers. this comes from the difficult math questions doc..

Of a group of 260 people who purchased stocks, 61 purchased A, 88 purchased B, 56 purchased C, 75 purchased D, 60 purchased E. what is the greatest possible number of the people who purchased both B and D?

A:40
B:50
C:60
D:75
E:80
Top
Source: — Problem Solving |
Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Fri Feb 02, 2007 11:15 am

by telugupilla » Fri Feb 02, 2007 1:18 pm
E: 80?

Sorry is the answer = 75?
Last edited by telugupilla on Fri Feb 02, 2007 1:38 pm, edited 1 time in total.
Top

GMAT/MBA Expert

User avatar
Site Admin
Posts: 6778
Joined: Mon Feb 13, 2006 8:30 am
Location: Los Angeles, CA
Thanked: 1249 times
Followed by:994 members

by beatthegmat » Fri Feb 02, 2007 1:27 pm
telugupilla wrote:E: 80?
Hi telugupilla:

Can you show your explanation as well? Thanks!
Beat The GMAT | The MBA Social Network
Community Management Team

Research Top GMAT Prep Courses:
https://www.beatthegmat.com/gmat-prep-courses

Research The World's Top MBA Programs:
https://www.beatthegmat.com/mba/school
Top
Newbie | Next Rank: 10 Posts
Posts: 6
Joined: Fri Feb 02, 2007 11:15 am

by telugupilla » Fri Feb 02, 2007 1:37 pm
Total No of people= 260

No. of people who purchased A+B+C+D+E =
61+88+56+75+60 = 340

So atleast 340-260 = 80 people would have bought more than 1 stock.

But to buy both B and D it would have to 75 people.

Im sorry answer = 75 people
Top
Master | Next Rank: 500 Posts
Posts: 354
Joined: Tue Jun 27, 2006 9:20 pm
Thanked: 11 times
Followed by:5 members

oa

by 800guy » Mon Feb 05, 2007 2:51 pm
here's the oa..

ANSWER is D (75)

since they have asked us to find out the greatest possible number buying both B as well as D, the answer has to be the smallest no between the two which is 75...as all the guys purchasing D can also buy B and only 75 out of 88 purchasing B can simultaneously purchase D as well....
Top
Moderator
Posts: 772
Joined: Wed Aug 30, 2017 6:29 pm
Followed by:6 members

re:

by BTGmoderatorRO » Sat Sep 16, 2017 6:21 pm
from the question, 260 people purchased stocks.
people who purchased stock A = 61
B = 88
C = 56
D = 75
E = 60

The question asked us to find the greatest possible number of people who purchased B and D.
so, adding the total number of people that purchased A,B,C,D,E, we have 61+88+56+75+60=340

340-260= 80 (meaning that at least, one person will buy more than one stock).

To get the greatest possible number of those that purchase stock B and D, then we will consider the least number of stock purchased in these two categories.
since 88 purchased B, and 75 purchased D.
Then, 75 of people who purchased D also purchased B.

so, option D is right
Top
Post new topic Post Reply
• Page 1 of 1