BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Problem solving:Prime numbers.

Expert replies
by ash4gmat » Mon Nov 09, 2015 9:41 am
Hi, Came across with this data sufficiency question where my solution is same but don't agree with the answers provided. Help me solve this.

Q)A Pierpont prime is any prime number p such that p = (2 k )(3 l )+1 , where k and l are non-negative integers. If r is an integer, is r a Pierpont prime?
1.1 < r < 5
2.0 < r < 4


ABCDE?
Join the discussion
Source: — Problem Solving |

by [email protected] » Mon Nov 09, 2015 10:49 am
Hi ash4gmat,

This really should have been posted in the DS Forum, but I'll be happy to walk you through it:

We're told that a Pierpont prime is any PRIME number p such that p = (2^K)(3^L)+1, where K and L are non-negative integers. We're told that R is an INTEGER. We're asked if R a Pierpont prime. This is a YES/NO question.

1) 1 < R < 5

From this Fact, R is limited to only 3 possibilities: 2, 3 and 4. We have to check to see if they fit the definition of a Pierpont prime...

IF...
R = 2, then K = 0 and L = 0 would give us R = (1)(1) + 1 = 2, so R IS a Pierpont Prime and the answer to the question is YES.

R = 3, then K = 1 and L = 0 would give us R = (2)(1) + 1 = 3, so R IS a Pierpont Prime and the answer to the question is YES.

R = 4, then the answer to the question is NO (since 4 is NOT a prime number)
Fact 1 is INSUFFICIENT

2) 0 < R < 4

This Fact also limits R to only 3 possibilities: 1, 2 and 3. Our prior work (in Fact 1, above) will be useful here...

IF....
R = 1, then the answer to the question is NO (since 1 is NOT a prime number)

R = 2 or R = 3, then the answer to the question is YES (the work above proves this).
Fact 2 is INSUFFICIENT

Combined, we know...
1 < R < 5
0 < R < 4

R can ONLY be 2 or 3. Since both of those numbers lead to the same "YES" answer, the answer to the question is ALWAYS YES.
Combined, SUFFICIENT

Final Answer: C

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
Image
Join the discussion

by Anaira Mitch » Wed Nov 21, 2018 6:14 am
Hello All,

Is there any other method to solve this question?
Join the discussion