Problem Solving for 780+ Aspirants.

sureshbala wrote:

Musiq wrote:

sureshbala wrote:

axat wrote:Hi Suresh

The questions you post here are exciting and challenging, but are you sure GMAT(even at a 99%ile difficulty level) matches questions such as these?

I doubt that. Also, where have you had the experience of 6 years as a GMAT tutor?

In any case, thanks for the effort.

Hi,

Probably the initial questions in this thread are quite tough and the scope for them to appear in the GMAT may be quite low but the questions after the first 3 or 4 are definitely much within the standard of the GMAT.

By the way, I worked for TIME and CL as a mentor/content developer.

Regards

Hi Suresh,

I used to teach at TIME ( Andhra Pradesh). Mr. J.V. Murthy was my boss.

I really loved that experience.....it's nice to see TIME being mentioned.

That's nice to hear...My first boss is also Mr.JVM. I learnt a lot during my career as a mentor in TIME, Vizag. I worked there from 2003-2006.

@yogami..thanks for the post...nice to hear that this thread helped you to brush up the concepts

sureshbala wrote:Here is the next question....

Participation in the local soccer league this year is 10% higher than last year.The number of males increased by 5% and the number of females increased by 20%. What fraction of the soccer league is now female?

A. 1/3

B. 4/11

C. 2/5

D. 4/9

E. 1/2

sureshbala wrote:Here is the next one.....

Two positive numbers x and y are such that their LCM = 1188 and their HCF = 12. If x + y = 240, then find the smaller of the two numbers x and y.

A. 96

B. 108

C. 84

D. 144

E. None of these

Factor the LCM

LCM =2^2 x 3^3 x 11

GCF = 2^2 x 3

If LCM and GCF has 2^2 then both numbers Must have it. If GCF has 3 the one of them has only 3 and the other has 3^3. Since 11 is not in GCF only one of them can have 11. Assigning 11 to the factor with a single 3 meets the 240 condition.

X= 2^2 x 3^3

Y = 2^2 x 3 x 11

Smallest is 27 x 4 =108

Choose B.

sureshbala wrote:Here is the next one.....

Two positive numbers x and y are such that their LCM = 1188 and their HCF = 12. If x + y = 240, then find the smaller of the two numbers x and y.

A. 96

B. 108

C. 84

D. 144

E. None of these

abhinav85 wrote:IMO B.

If LCM=1188 and HCF=12.

To get the product of x and y. multiply LCM with HCF,1188 x 12 = 14236.

Now we can see that 6 is in the unit's digit place.

Just go through the answer choices and look for combination
which ends with 6 in the end.........i e 108 x 132..........8 x 2 = 16.

Answer B.

I thought about this but at the 720+ level, I would'nt take chances with None of the Above.