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Problem solving: Difficulty level: 700, Source: Princeton

Expert replies
by aishwaryav12 » Sat Oct 06, 2018 11:20 pm
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Which of the following integers can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers?

A. 49
B. 70
C. 140
D. 215
E. 525
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Source: — Problem Solving |

by GMATGuruNY » Sun Oct 07, 2018 3:10 am
aishwaryav12 wrote:Which of the following integers can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers?

A. 49
B. 70
C. 140
D. 215
E. 525
For any evenly spaced set:
sum = (number)(median)

We can PLUG IN THE ANSWERS, which represent the sum.
Since the number of integers can be 5 or 7, the sum must be a multiple of both 5 and 7.
Eliminate A, which is not divisible by 5.
Eliminate D, which is not divisible by 7.

The equation in blue can be rephrased as follows:
median = sum/number
Since all of the integers must be odd, the correct answer must yield an odd value for the median.

If B is the sum of 7 consecutive odd integers, we get:
median = sum/number = 70/7 = 10.
Since the yielded median is not odd, eliminate B.
If D is the sum of 7 consecutive odd integers, we get:
median = sum/number = 140/7 = 20.
Since the yielded median is not odd, eliminate D.

The correct answer is E.
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by fskilnik@GMATH » Sun Oct 07, 2018 7:00 am
aishwaryav12 wrote:Which of the following integers can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers?

A. 49
B. 70
C. 140
D. 215
E. 525
$$?\,\,\,:\,\,\,\,\sum\nolimits_5 {\,{\rm{consecutive}}\,\,{\rm{odd}}\,\,{\rm{integers}}\,\,\,\, = \,} \,\,\,\,\sum\nolimits_7 {\,\,{\rm{consecutive}}\,\,{\rm{odd}}\,\,{\rm{integers}}} $$
> 5 consecutive odd integers are members of a finite arithmetic sequence, hence the middle term (one of them) is an odd integer and equal to their average.

(A) average 49/5 is not an integer, hence cannot be the middle term. Refuted.
(B) average 70/5 = 14 is not odd, hence cannot be the middle term. Refuted.
(C) average 140/5 = 28 is not odd, hence cannot be the middle term. Refuted.

> 7 consecutive odd integers are members of a finite arithmetic sequence, hence the middle term (one of them) is an odd integer and equal to their average.

(D) average 215/7 is not a multiple of 7 (210 is), hence cannot be the middle term. Refuted.

(E) is the answer by exclusion.

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
English-speakers :: https://www.gmath.net
Portuguese-speakers :: https://www.gmath.com.br
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by Scott@TargetTestPrep » Fri Oct 12, 2018 6:59 am
aishwaryav12 wrote:Which of the following integers can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers?

A. 49
B. 70
C. 140
D. 215
E. 525
If a number can be written as both the sum of 5 consecutive odd integers and 7 consecutive odd integers, then it’s a multiple of both 5 and 7. This eliminates choice A, 49 (since it’s only a multiple of 7) and choice D, 215 (since it’s only a multiple of 5). So we are left with 70, 140 and 525 to consider.

Not only must the sum be both a multiple of 5 and 7, but the sum also has to be odd (since the sum of five odd numbers must also be odd). This eliminates answer choices B and C and we are left with E.

Answer: E

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